更新列表中字典中值的类型

Question

有人能告诉我这个吗？：我有一个字典列表：[{'overall': 5.0,  'vote': 'overall',  'reviewerID': 'AAP7PPBU72QFM'}, {'overall': 3.0,  'vote': '5',  'reviewerID': 'A2E168DTVGE6SV'},...]如何将“总体”和“投票”项转换为整数，同时将所有非有效数字设置为 0？更清楚地说，所需的输出是：[{'overall': 5,  'vote': 0,  'reviewerID': 'AAP7PPBU72QFM'}, {'overall': 3,  'vote': 5,  'reviewerID': 'A2E168DTVGE6SV'},...]非常感激。

Answer 1

另一个解决方案很棒，这是可读性的另一个解决方案：

list_dicts = [{'overall': 5.0,

  'vote': 'overall',

  'reviewerID': 'AAP7PPBU72QFM'},

 {'overall': 3.0,

  'vote': '5',

  'reviewerID': 'A2E168DTVGE6SV'}]

def fix_key(d, k):

    try:

        d[k] = int(d[k])

    except:

        d[k] = 0

def fix(d):

    fix_key(d, 'vote')

    fix_key(d, 'overall')

    return d

list_dicts = [fix(d) for d in list_dicts]

# [{'overall': 5, 'vote': 0, 'reviewerID': 'AAP7PPBU72QFM'}, {'overall': 3, 'vote': 5, 'reviewerID': 'A2E168DTVGE6SV'}]

print(list_dicts)

Answer 2

def clean_value(x):

    try:

        return int(x)

    except ValueError:

        return 0

def clean_list_of_dicts(l):

    return [{

        k:v if k not in ('overall', 'vote') else clean_value(v) \

        for k, v in d.items()

    } for d in l]

对您的输入数据进行的测试表明该解决方案有效。

>>> clean_list_of_dicts([{'overall': 5.0,

  'vote': 'overall',

  'reviewerID': 'AAP7PPBU72QFM'},

 {'overall': 3.0,

  'vote': '5',

  'reviewerID': 'A2E168DTVGE6SV'}

])

给出输出：

[{'overall': 5,

  'vote': 0,

  'reviewerID': 'AAP7PPBU72QFM'},

 {'overall': 3,

  'vote': 5,

  'reviewerID': 'A2E168DTVGE6SV'}]

Answer 3

我希望它对你有用，但与函数一起使用会更好

for i in data:
  i['overall'] =int(i['overall'])
  i['vote'] = int(i['vote']) if (i['vote']).isdigit() else 0