Go 中如何删除空格

Question

我想删除字符串值中的空格，例如：“I d skd a efju N”到“IdskdaefjuN”，但它不起作用......我尝试使用：stringValue = strings.Replace(stringValue, " ", "", -1)package mainimport (    "fmt"    "strings")func main() {    //var String    var stringValue string    var originalValue string    fmt.Printf("please, type some text:")    //user input    fmt.Scan(&stringValue)    originalValue = stringValue    //remove spaces    stringValue = strings.Replace(stringValue, " ", "", -1)    //set string to lower case    stringValue = strings.ToLower(stringValue)    //if contains substring "i", "a" and "n"    if strings.Contains(stringValue, "i") && strings.Contains(stringValue, "a") && strings.Contains(stringValue, "n") {        // if "i" is a prefix and "n" a suffix        firstChar := strings.HasPrefix(stringValue, "i")        lastChar := strings.HasSuffix(stringValue, "n")        switch {        //if is a prefix and suffix so Found        case firstChar && lastChar:            fmt.Printf("Found in %s", originalValue)        //if isnt a prefix and suffix so Not Found        default:            fmt.Printf("Not Found in %s", originalValue)        }        //if there's no "i", "a" and "n"    } else {        fmt.Printf("Not Found in %s", originalValue)    }}

Answer 1

Go 中如何删除空格

例如，

package main

import (

    "fmt"

    "unicode"

)

func removeSpace(s string) string {

    rr := make([]rune, 0, len(s))

    for _, r := range s {

        if !unicode.IsSpace(r) {

            rr = append(rr, r)

        }

    }

    return string(rr)

}

func main() {

    s := "I d skd a efju N"

    fmt.Println(s)

    s = removeSpace(s)

    fmt.Println(s)

}

游乐场：https://play.golang.org/p/KoXZ24WXw7r

输出：

I d skd a efju N

IdskdaefjuN

Answer 2

我用过这个

func cleanSpaces(stringToClean string) string {

    result := strings.ReplaceAll(stringToClean, " ", "")

    return result

}

或者

func cleanSpaces(stringToClean string) string {

    fields := strings.Fields(stringToClean)

    var result string

    for i := 0; i < len(fields); i++ {

       result += fields[i]

    }

    return result

}

Answer 3

当我尝试运行您的代码时，它没有正确使用fmt.Scan(). 如果将其替换为从 stdin 读取的缓冲读取器，则它可以工作：

package main

import (

    "bufio"

    "fmt"

    "os"

    "strings"

)

func main() {

    //var String

    var stringValue string

    var originalValue string

    reader := bufio.NewReader(os.Stdin)

    fmt.Printf("please, type some text:")

    //user input

    stringValue, _ = reader.ReadString('\n')

    stringValue = strings.TrimSuffix(stringValue, "\n")

    originalValue = stringValue

    //remove spaces

    stringValue = strings.ReplaceAll(stringValue, " ", "")

    //set string to lower case

    stringValue = strings.ToLower(stringValue)

    //if contains substring "i", "a" and "n"

    if strings.Contains(stringValue, "i") && strings.Contains(stringValue, "a") && strings.Contains(stringValue, "n") {

        // if "i" is a prefix and "n" a suffix

        firstChar := strings.HasPrefix(stringValue, "i")

        lastChar := strings.HasSuffix(stringValue, "n")

        switch {

        //if is a prefix and suffix so Found

        case firstChar && lastChar:

            fmt.Printf("Found in %s", originalValue)

        //if isnt a prefix and suffix so Not Found

        default:

            fmt.Printf("Not Found in %s", originalValue)

        }

        //if there's no "i", "a" and "n"

    } else {

        fmt.Printf("Not Found in %s", originalValue)

    }

}

Answer 4

这对我有用

package main

import (

    "fmt"

    "strings"

)

func main() {

    x := "       1    ,2,   3,4,6     -3   0, 7,   8,70   -9   0"

    x = strings.Replace(x, " ", "", -1)

    fmt.Println(x)

}

只需将空格替换为空字符串，请参阅此处的官方文档