2 回答

TA贡献1829条经验 获得超7个赞
我认为您真正想知道的是如何创建数组引用。您可以通过在数组名称前添加 & 符号来实现此目的
<?php
$arrayWithPrettyLongName = [
'level_1' => [
'key_1' => 10,
'key_2' => 20,
'key_3' => 30,
]
];
// Test-1 // Works fine!
$result_1 =
$arrayWithPrettyLongName['level_1']['key_1'] +
$arrayWithPrettyLongName['level_1']['key_2'] +
$arrayWithPrettyLongName['level_1']['key_3'] ;
echo $result_1;
echo "\n";
//Just create an array reference here, by preceding the name with an `&`
$path = &$arrayWithPrettyLongName['level_1'];
//Also remove the `.` symbol here. That's not the correct syntax
$result_2 =
$path['key_1'] +
$path['key_2'] +
$path['key_3'] ;
echo $result_2;
但看!如果你真的想减少代码,难道就不能这样做吗?
$result_3 = 0;
foreach ($arrayWithPrettyLongName['level_1'] as $value){
$result_3 += $value;
}
echo $result_3;
如果以后数组变大,保存就会很麻烦。

TA贡献1784条经验 获得超2个赞
像这里一样工作:
<?php
$arrayWithPrettyLongName = [
'level_1' => [
'key_1' => 10,
'key_2' => 20,
'key_3' => 30,
]
];
// Test-1
$result_1 =
$arrayWithPrettyLongName['level_1']['key_1'] +
$arrayWithPrettyLongName['level_1']['key_2'] +
$arrayWithPrettyLongName['level_1']['key_3'] ;
echo $result_1; //output 60
// Test-2
$path = $arrayWithPrettyLongName['level_1'];
$result_2 =
$path['key_1'] +
$path['key_2'] +
$path['key_3'] ;
echo $result_2; //output 60
?>
你错了$path = "$arrayWithPrettyLongName['level_1']";必须是没有""
另一个改变是$path .必须是$path['key_1'];
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