Laravel 多图上传

Question

我正在尝试保存多个图像，但帖子底部的图像中显示错误。我尝试过请求名称，但出现另一个错误，属性和图像之间存在一对多关系，我正在尝试保存属性的许多图像。如果我收到图像，如果我在创建之前进行 dd 操作，我就会收到图像。存储方法public function store(Request $request){  /*--from this session you start to save the properties with all their attributes  --*/      $properti = new Propertie;    $detail = new Detail;    $detail->antiquity = $request->antiquity;    $detail->furnished = $request->furnished;    $detail->floor = $request->floor;    $detail->save();    $properti->details_id = $detail->id;    $properti->name = $request->name;    $properti->price = $request->price;    $properti->description = $request->description;    $properti->departaments_id = $request->departaments;    $properti->municipalities_id = $request->municipalities;    $properti->property_type_id = $request->type_property;    $properti->offer_type_id = $request->type;    $properti->details_id = $detail->id;    $properti->lat = $request->lat;    $properti->lng = $request->lng;    $properti->address = $request->address;    if (isset($request->property_id)) {        $property_type = $request->property_id;    } else {        $property_type = null;    }            $properti->save();        $image->name = $request->name;                   foreach($request->file('images') as $image ){             $name = $image->getClientOriginalName();            $image->move('image',$name);        }            $properti->images()->create(['name' => $name ]);    $piso_id = $properti->id;    $space = new Space;    $space->property_id = $piso_id;    $space->bedrooms = $request->bedrooms;    $space->bathrooms = $request->bathrooms;    $space->parking = $request->parking;    $space->area = $request->area;    $space->save();    $properti->spaces_id = $space->id;    foreach ($request->input('characteristic') as $characteristic) {        $charc = new Characteristic;        $charc->property_id = $piso_id;        $charc->characteristic = $characteristic;        $charc->save();    }

Answer 1

看起来只有在没有附加图像的情况下才会发生此错误。您应该在循环请求数据时附加图像：

foreach ($request->file('images') as $image) { 

    $name = $image->getClientOriginalName();

    $image->move('image', $name);

    // v- TO HERE -v

    $properti->images()->create(['name' => $name ]);

}

// MOVE THIS: $properti->images()->create(['name' => $name ]);

Answer 2

正如我所看到的，您正在调用在 foreach 循环内定义的变量 $name ，这意味着它没有在循环外定义，这就是错误所说的。