从 2 个输入转换 Laravel 中的时间

Question

我是 Laravel 的初学者。我在我的项目 Laravel 6 中使用。我有 2 个输入：<input maxlength="5" type="text" name="hours_worked" class="form-control edited valid" value="" required="" onkeypress="return isNumberKey(event)"><input type="text" name="minutes_worked" class="form-control edited valid" value="" required="" onkeypress="return isNumberKey(event)">我用以下代码保存到数据库：WorkingTime::create( $this->request->all()例如，当有人在字段中输入时，我会遇到问题。“90”分钟。我在数据库中保存了 90 分钟 - 我想节省 1 小时 30 分钟。我怎样才能用我的代码实现这个目标？我的架构：Schema::create('working_times', function (Blueprint $table) {            $table->increments('id');            $table->integer('client_id')->unsigned();            $table->foreign('client_id')->references('id')->on('clients')->onDelete('cascade');            $table->integer('case_id')->unsigned();            $table->foreign('case_id')->references('id')->on('case_instances')->onDelete('cascade');            $table->integer('user_id')->unsigned();            $table->foreign('user_id')->references('id')->on('users')->onDelete('cascade');            $table->smallInteger('hours_worked');            $table->smallInteger('minutes_worked');            $table->string('name');            $table->string('appearance')->nullable();            $table->longText('description')->nullable();            $table->softDeletes();            $table->timestamps();        });

Answer 1

这是一个粗略的解决方案，但不是这样做：

WorkingTime::create($this->request->all());

做：

$data = $this->request->all();

$hours = (int) $data['hours_worked'];

$minutes = (int) $data['minutes_worked'];

$overMinutes = $minutes % 60;

$hours += (int) (($minutes - $overMinutes) / 60);

$minutes = $overMinutes;

$data['hours_worked'] = $hours;

$data['minutes_worked'] = $minutes;

WorkingTime::create($data);