如何在 javascript 中使用集合并获得相同的结果

Question

在 javascript 中，我有 2 个 seta，并从 A 组中删除 B 组A 组：7,8,9,10 B 组：8,9结果应该是：7,10使用 var availableA = [...new Set([...workingA].filter(x => !b1.has(x)))];结果不正确我可以用什么来区别？

Answer 1

这可能就是您正在寻找的：

function padHours(str) {

    const [minutes, seconds] = str.match(/\d{1,2}/g);

    return (minutes.length < 2 ? '0' + minutes : minutes) + ':' + seconds;

}

const a = new Set(['07:00', '08:00', '09:00', '10:00', '11:00', '12:00', '13:00', '14:00', '15:00', '16:00', '17:00', '18:00'].map(padHours));

const b = new Set(['07:00', '8:00', '9:00', '15:00', '16:00', '17:00', '11:00', '12:00', '13:00'].map(padHours));

// Converting to an array allows to filter (which is not possible on Sets)

const arr = [...a, ...b].filter(x => !a.has(x) || !b.has(x));

console.log(arr);

// And if you absolutely want the result as a Set

const result = new Set(arr);

console.log(result);