我试图同时将数据插入两个表中。第一个条件 IF 可以,但第二个条件 ELSE 不行。我在下面添加了我的插入代码。我已经尝试过使用 ELSE、ELSEIF 甚至 IF,但它不起作用。if (isset($_POST['save')) { if (@$_POST['id_confrontations'] == "") { @$description = $_POST['description']; @$dt_confrontation = $_POST['dt_confrontation']; @$id_competitions = $_POST['id_competitions']; @$id_stages = $_POST['id_stages']; @$score1 = $_POST['score1']; @$score2 = $_POST['score2']; @$mandant_club = $_POST['mandant_club']; @$visitor club = $_POST['visitor_club']; @$situation = $_POST['situation']; @$phase = $_POST['phase']; @$id_trainers = $_POST['id_trainers']; @$history = $_POST['history']; //saves the record in the "confrontations" table - In this case insertion is perfect $confrontations = "INSERT INTO confrontations (description, dt_confrontation, id_competitions, stadiums_id, score1, scoring2, binder_club, situation, stage, id_trainers, history) VALUES ('$description','$dt_confrontation','$id_competitions', '$id_estadios','$score1','$score2', '$mandant_club','$visitor_club','$situation', '$stage','$id_trainers','$historia')'; //saves the record in the "panel" table - In IF insertion is perfect, but in ELSE it inserts as if it were IF //In the IF rule the mandating_club would be == '1', so the GF would receive the score1 and the GC would receive the score2 //In the ELSE rule the visiting_club would be == '1', so the GC would receive the score1 and the GF would receive the score2感谢大家的关注和建议。
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白衣非少年
TA贡献1155条经验 获得超0个赞
您的代码有大量错误数据和缺少变量
该变量@$visitorclub = $_POST['visitor_club']; 应该@$visitor_club
您声明变量 @$history = $_POST['history']; 但是当将数据插入 [confrontations] 表时,您会调用 $historia 变量。
您以 ["] 双引号开始将数据插入表 [confrontations],但以 ['] 单引号结束。
您的表 [对抗] 的插入代码。您声明 [11] 列名称,但声明 [12] 列值。因此,您现在应该将相同的列名称和值添加到数据插入代码中。
当您将数据插入[面板]表时,您的代码如下
插入面板(GF、GC、binant_club、visitor_club、id_competitions、状态、状态)
这里最后两列(状态,状态)名称相同。您不能使用相同的列名插入数据。
注意:如果你想用MySQL创建插入代码。转到 PHP MyAdmin 并选择您的数据库 >> 选择您的表 >> 单击插入 >> 插入虚拟数据 >> 现在 MySQL 为 PHP 生成自动插入代码。使用此代码通过更改列值插入数据。
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