使用 array_diff 后以对象形式获取答案

Question

我正在比较 2 个数组，但在应用 array_diff 后，它以对象形式返回结果。看看下面的代码和结果<?php        $schedule =  ['Monday'=>['12:00','01:20'],'Tuesday'=>['04:00','12:00','20:00']];        $booked_slots =  ['Monday'=>['12:00'],'Tuesday'=>['20:00']];                $diff = [];        foreach ($schedule as $day =>  $times) {            $day_wise_slots = isset($booked_slots[$day]) ? $booked_slots[$day] : [];            $diff[$day] = array_diff($times, $day_wise_slots);        }                echo json_encode($diff);?>结果：{"星期一":{"1":"01:20"},"星期二":["04:00","12:00"]}所需输出：{“星期一”：[“01:20”]，“星期二”：[“04:00”，“12:00”]}

Answer 1

array_diff保留原始数组的键。您需要重新初始化数组，以使 json 中没有数组键。您可以使用array_values来获取重新初始化的数组键

<?php

       $schedule =  ['Monday'=>['12:00','01:20'],'Tuesday'=>['04:00','12:00','20:00']];

       $booked_slots =  ['Monday'=>['12:00'],'Tuesday'=>['20:00']];

       

       $diff = [];

       foreach ($schedule as $day =>  $times) {

           $day_wise_slots = isset($booked_slots[$day]) ? $booked_slots[$day] : [];

           $diff[$day] = array_values(array_diff($times, $day_wise_slots));

       }

       

       echo json_encode($diff);

?>