当我尝试从登录页面（index.php）加载上面的 php 页面时，没有错误，但是当我登录后尝试从应用程序中的任何其他页面加载它时，它在控制台上给我一个未捕获的语法错误。它指向脚本并表示 php 变量 $name 未定义。<?phpif (isset($_POST["login"])) {session_start();$_SESSION["email"] = $_POST["email"];$email = $_POST["email"];$password = $_POST["password"];$dbhost = 'localhost';$dbuser = 'root';$dbpass = '';$dbname = 'attendance_system';$conn = new mysqli($dbhost, $dbuser, $dbpass, $dbname);if ($conn->connect_error) { die("Failed to connect: " . $conn->connect_error);} else { $success = false; $query = "SELECT * FROM student"; $result = $conn->query($query); while ($row = $result->fetch_assoc()) { if ($row["email"] === $email && $row["password"] === $password) { $name = $row["name"]; $age = $row["age"]; $criteria = $row["attendance_criteria"]; $course = $row["course"]; $college = $row["college_name"]; $attendance = $row["attendance"]; $success = true; break; } } if ($success === false) { header("Location: index.php"); }}}if (isset($_POST["signup"])) {session_start();$_SESSION["email"] = $_POST["email1"];$email = $_POST["email1"];$password = $_POST["password1"];$name = $_POST["name"];$age = $_POST["age"];$criteria = 100;$course = null;$college = null;$attendance = 0;$dbhost = 'localhost';$dbuser = 'root';$dbpass = '';$dbname = 'attendance_system';$conn = new mysqli($dbhost, $dbuser, $dbpass, $dbname);if ($conn->connect_error) { die("Failed to connect: " . $conn->connect_error);} else { $query = "INSERT INTO student SET email = '$email', name = '$name', age = '$age', password = '$password' "; $result = $conn->query($query);}}?><!DOCTYPE html><html><head><meta charset="UTF-8"><meta name="viewport" content="width=device-width"><title>Attendance Manager - Home</title><link rel="stylesheet" href="../css/skeleton.css"><link rel="stylesheet" href="../css/home.css"><link rel="icon" type="image/jpg" href="../media/icon.png"></head>
1 回答
潇湘沐
TA贡献1816条经验 获得超6个赞
如果您的页脚<script>始终运行并且始终期望$name被填充，那么您必须检查会话是否已登录。如果未登录，请将用户重定向到登录页面，或指定默认值。
另外，您可能应该重写用于验证用户身份的 SQL。首先，将密码保存为哈希值。其次，使用WHERE语句来获取与电子邮件和密码匹配的任何行，而不是循环访问应用程序中的结果。
您可能还想修复var pasword拼写错误，我建议您将$success变量重命名为更具描述性的名称，例如$loggedIn. 对于这个特定目的来说，这可能并不重要，但养成正确命名变量的习惯是一件好事。
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