这是我的代码:for i in matches: driver.get(i) Country = WebDriverWait(driver, 2).until(EC.visibility_of_element_located((By.XPATH, "/html/body/div[4]/div[5]/div/div/div[1]/section/ul/li[3]/a"))).text leagueseason = WebDriverWait(driver, 2).until(EC.visibility_of_element_located((By.XPATH, "/html/body/div[4]/div[5]/div/div/div[1]/section/header/h1/a"))).text Date = WebDriverWait(driver, 2).until(EC.visibility_of_element_located((By.ID, 'match-date'))).text Date = Date.replace(".", "/").replace("-", "").replace(" ", "", 1) Home = WebDriverWait(driver, 2).until(EC.visibility_of_element_located((By.XPATH, "/html/body/div[4]/div[5]/div/div/div[1]/section/ul[2]/li[1]/h2/a"))).text Away = WebDriverWait(driver, 2).until(EC.visibility_of_element_located((By.XPATH, "/html/body/div[4]/div[5]/div/div/div[1]/section/ul[2]/li[3]/h2/a"))).text ft = WebDriverWait(driver, 2).until(EC.visibility_of_element_located((By.ID, 'js-score'))).text Res = "" try: extrainfo = driver.find_element_by_xpath("//*[@id='js-eventstage']").text except NoSuchElementException: extrainfo = " "现在我会TimeoutException在页面未加载时添加一个,我尝试这样做:try: #previous codeexcept TimeoutException: driver.get(i)这样,当我遇到超时错误时,代码将跳过 url 抓取并继续处理下一个 url。我该如何解决这个问题?我希望在超时的情况下它会重新加载页面并再次抓取该网址的数据。
1 回答
大话西游666
TA贡献1817条经验 获得超14个赞
您可以将其放入 while 循环中,一旦成功完成,就会继续。所以像这样:
success = False
while success == False:
try:
# previous code
success = True
except TimeoutException:
print ('Will try again...')
添加回答
举报
0/150
提交
取消