在 PHP 中第一次替换后停止替换字符串中的文本

Question

这是一个例子：$original_string = 'I like apples very much. I want an apple.';$temp_string = str_replace('apples', '_apples_', $original_string);// $temp_string is now: I like _apples_ very much. I want an apple.$final_string = str_replace('apple', '_apple_', $temp_string);// $final_string is now: I like __apple_s_ very much. I want an _apple_.这不是我打算做的。我希望最终的字符串是：I like _apples_ very much. I want an _apple_.这就是我试图做的：$original_string = 'I like apples very much. I want an apple.';$final_string = str_replace(['apples', 'apple'], ['_apples_', '_apple_'], $original_string);echo $original_string;// I like __apple_s_ very much. I want an _apple_. 颠倒更换顺序也无济于事：$original_string = 'I like apples very much. I want an apple.';$original_string = str_replace(['apple', 'apples'], ['_apple_', '_apples_'], $original_string);echo $original_string;// I like _apple_s very much. I want an _apple_. 我应该怎么办？

Answer 1

您可以使用preg_replace它使用正则表达式而不是字符串进行替换

$original_string = 'I like apples very much. I want an apple.';

$final_string = preg_replace("/(apples?)/", "_$1_", $original_string);

echo $final_string;

正则表达式解释： https: //regex101.com/r/EzxqWR/2和演示： https: //3v4l.org/uTDIs

                  (1)         (2)

               vvvvvvvv      vvvv

preg_replace("/(apples?)/", "_$1_", $original_string);

1. 它将搜索字符串apple或apples

2. 并将结果放入$1and 成为_apple_or_apples_

希望解释清楚，对于不好的解释表示歉意