我使用 Ajax 进行 PHP 用户名验证,将我的 html 页面复制到 html div(用于显示 ajax 错误)元素内。我尝试了一些解决方案并谷歌搜索但找不到其他解决方案。也许问题出在 $_POST 上,但我也在 php 中将它们分开(所有输入验证)。这是 PHP 代码<?php if(isset($_POST['username'])){ //username validation $username = $_POST['username']; if (! $user->isValidUsername($username)){ $infoun[] = 'Your username has at least 6 alphanumeric characters'; } else { $stmt = $db->prepare('SELECT username FROM members WHERE username = :username'); $stmt->execute(array(':username' => $username)); $row = $stmt->fetch(PDO::FETCH_ASSOC); if (! empty($row['username'])){ $errorun[] = 'This username is already in use'; } }}if(isset($_POST['fullname'])){ //fullname validation $fullname = $_POST['fullname']; if (! $user->isValidFullname($fullname)){ $infofn[] = 'Your name must be alphabetical characters'; } }if(isset($_POST['password'])){ if (strlen($_POST['password']) < 6){ $warningpw[] = 'Your password must be at least 6 characters long'; } }if(isset($_POST['email'])){ //email validation $email = htmlspecialchars_decode($_POST['email'], ENT_QUOTES); if (! filter_var($email, FILTER_VALIDATE_EMAIL)){ $warningm[] = 'Please enter a valid email address'; } else { $stmt = $db->prepare('SELECT email FROM members WHERE email = :email'); $stmt->execute(array(':email' => $email)); $row = $stmt->fetch(PDO::FETCH_ASSOC); if (! empty($row['email'])){ $errorm[] = 'This email is already in use'; } }}
- 1 回答
- 0 关注
- 108 浏览
添加回答
举报
0/150
提交
取消