为什么要打印第一个索引？

Question

在 python 课程中解决这个问题，但我终生无法弄清楚为什么这行不通。我宁愿它给我一个错误也不愿打印 0！问题给了我显示的字符串的变量x，需要打印第一次y使用的索引。x = 'Poisson geometry plays an important role in noncommutative geometry.'y = 'u'i = 0while i == 0:    for o in x:        if o == y:            print(y, "is first seen in index = ", y.index(o))            i += 1显示的代码返回：u is first seen in index =  0

Answer 1

你想要索引x吗？在这种情况下，使用x.index(o)where 搜索oin x。

x = 'Poisson geometry plays an important role in noncommutative geometry.'

y = 'u'

i = 0

while i == 0:

    for o in x:

        if o == y:

            print(y, "is first seen in index = ", x.index(o))

            i += 1

然而，正确的写法是没有循环：

x = 'Poisson geometry plays an important role in noncommutative geometry.'

y = 'u'

print(y, "is first seen in index = ", x.index(y))

输出：

u is first seen in index =  51

Answer 2

您实际上是在寻找'u'.index('u')

y.index(o)应该是x.index(o)这个例子。

Answer 3

你需要迭代吗？如果您保留前 2 行然后使用，您将在不使用,或 的情况下x.index(y)获得相同的结果。whileforif

x = 'Poisson geometry plays an important role in noncommutative geometry.'

y = 'u'

print(y, "is first seen in index = ", x.index(y))