如何从字符串中删除某些数据？

Question

此代码输出特定马匹的时间戳和赔率。我想从代码的输出中删除时间戳。我的代码：request2 = requests.get('https://www.punters.com.au/api/web/public/Odds/getOddsComparisonCacheable/?allowGet=true&APIKey=65d5a3e79fcd603b3845f0dc7c2437f0&eventId=1045618&betType=FixedWin', headers={'User-Agent': 'Mozilla/5.0'})json2 = request2.json()for selection in json2['selections']:    for fluc in selection['flucs'][0]:        data = ast.literal_eval(selection['flucs'])        print(data[-2:])代码输出：[[1598060018, 12.97], [1598060095, 13.13]][[1598060066, 4.41], [1598060095, 4.36]][[1598060030, 2.11], [1598060095, 2.12]][[1598060030, 5.69], [1598060095, 5.61]][[1598059986, 16.35], [1598060095, 16.6]][[1598060006, 12.06], [1598060095, 12.35]][[1598060026, 25.83], [1598060095, 26.25]][[1598060026, 39.25], [1598060095, 39.83]]代码的期望输出：[[12.97], [13.13]][[4.41], [4.36]][[2.11], [2.12]]

Answer 1

以下

data = [[1598060018, 12.97], [1598060095, 13.13]]

new_data = [[x[1]] for x in data]

print(new_data)

输出

[[12.97], [13.13]]

Answer 2

for lsst in new data:

    a=[str(item) for item in lsst if "." not in lsst]

或者

if type==float:

    "keep it"

else:

    "remove .. delete whatever"