我对 PHP 中的数组有疑问：我有很多 zip 文件，里面有很多数据，使用 preg_grep 我可以得到以下结果：（这些数据是从 zip 文件中的多个文本文件返回的） => Array ( [ZipName] => data.zip [Age] => 45 ) => Array ( [ZipName] => data.zip [Name] => John ) => Array ( [ZipName] => data2.zip ) => Array ( [ZipName] => data1.zip [Age] => 25 ) => Array ( [ZipName] => data2.zip [Age] => 27 ) => Array ( [ZipName] => data1.zip [Name] => Abram ) => Array ( [ZipName] => data1.zip ) => Array ( [ZipName] => data2.zip [City] => London ) => Array ( [ZipName] => data2.zip [Name] => Inna ) => Array ( [ZipName] => data1.zip [City] => London )那么我如何使用 ZipName Value 组合/合并所有这些数组！就像在 SQL 中一样简单：SELECT * FROM * WHERE ZipName= 'x';0 => Array ( [ZipName] => data.zip [Age] => 45 [Name] => John [City] => Leicester )1 => Array ( [ZipName] => data1.zip [Age] => 25 [Name] => Abram [City] => London )2 => Array ( [ZipName] => data2.zip [Age] => 27 [Name] => Inna [City] => London )
3 回答
牛魔王的故事
TA贡献1830条经验 获得超3个赞
array_merge使用 等的替代方法array_combine...只是两个简单的 foreach 循环并将值设置到一个新数组 ( $new_arr) 中。
$new_arr = [];
foreach($arr as $inner_arr) {
foreach($inner_arr as $key=>$value) {
$new_arr[$key] = $value;
}
}
更新 我不清楚 OP 想要什么，但我希望现在更清楚了：
试试这个：（ 基本上将值添加到array[name of ZipName][{current key for the inner array}]
$arr = [
[
'ZipName' => 'data.zip',
'Age' => '45'
],
[
'ZipName' => 'data.zip',
'Name' => 'John'
],
[
'ZipName' => 'data2.zip',
'Age' => '27'
],
[
'ZipName' => 'data1.zip',
'Name' => 'Abram'
],
[
'ZipName' => 'data1.zip'
],
[
'ZipName' => 'data2.zip',
'City' => 'London'
],
[
'ZipName' => 'data2.zip',
'Name' => 'Inna'
],
[
'ZipName' => 'data1.zip',
'City' => 'London'
]
];
$new_arr = [];
foreach($arr as $key => $inner_arr) {
foreach($inner_arr as $ik => $item) {
$new_arr[$inner_arr['ZipName']][$ik] = $item;
}
}
输出：
Array
(
[data.zip] => Array
(
[ZipName] => data.zip
[Age] => 45
[Name] => John
)
[data2.zip] => Array
(
[ZipName] => data2.zip
[Age] => 27
[City] => London
[Name] => Inna
)
[data1.zip] => Array
(
[ZipName] => data1.zip
[Name] => Abram
[City] => London
)
)
做的时候：
$new_arr = array_values($new_arr);
关键只是做一个数字索引（如果重要的话）
Array
(
[0] => Array
(
[ZipName] => data.zip
[Age] => 45
[Name] => John
)
[1] => Array
(
[ZipName] => data2.zip
[Age] => 27
[City] => London
[Name] => Inna
)
[2] => Array
(
[ZipName] => data1.zip
[Name] => Abram
[City] => London
)
)
qq_遁去的一_1
TA贡献1725条经验 获得超7个赞
您需要的是按索引处的唯一值进行分组['ZipName']，然后分别合并这些组。这可以通过.array_reduce
例子：
<?php
declare(strict_types=1);
$input = [
[
'ZipName' => 'data_1.zip',
'Age' => 45,
], [
'ZipName' => 'data_1.zip',
'Name' => 'John',
], [
'ZipName' => 'data_1.zip',
], [
'ZipName' => 'data_1.zip',
'City' => 'Leicester',
],
[
'ZipName' => 'data_2.zip',
'Age' => 45,
], [
'ZipName' => 'data_2.zip',
'Name' => 'John',
], [
'ZipName' => 'data_2.zip',
], [
'ZipName' => 'data_2.zip',
'City' => 'Leicester',
],
];
$output = array_values(array_reduce($input, static function (array $acc, array $item): array {
$acc[$item['ZipName']] = array_merge($acc[$item['ZipName']] ?? [], $item);
return $acc;
}, []));
print_r($output);
慕桂英3389331
TA贡献2036条经验 获得超8个赞
我想你要组合不同的数组，所以请使用数组合并。
$array0 = Array
(
"ZipName" => data.zip,
"Age" => 45
);
$array1 = Array
(
"ZipName" => data.zip,
"Name" => John
);
$array2 = Array
(
"ZipName" => data.zip
);
$array3 = Array
(
"ZipName" => data.zip,
"City" => Leicester
);
print_r(array_merge($array0, $array1, $array2, $array3));
输出：
Array ( [ZipName] => datazip
[Age] => 45
[Name] => John
[City] => Leicester )
- 3 回答
- 0 关注
- 120 浏览
添加回答
举报
0/150
提交
取消