Node.js 正则表达式删除 url 中的撇号

Question

我需要替换我的字符串中的所有撇号，只有 href=" " 标签中的那些，外面的撇号应该保留。我正在使用 node.js。这是我的字符串：This is an example text. I'd love to fix this. <a href="https://www.example.com/i'd-love-to-fly/"> I'd love to fly link </a> Inside the text there could be more urls <a href="https://www.example.com/i'd-rather/">I'd rather link</a>. 例如<a href="https://www.example.com/i'd-love-to-fly/"> I'd love to fly link </a> 应该<a href="https://www.example.com/id-love-to-fly/"> I'd love to fly link </a> 我正在尝试使用正则表达式/https[^"]++/它选择了整个 URL，但我不知道如何只选择和替换撇号

Answer 1

假设您在 URL 中只有一个单引号：

(href="[^"]+)'([^"]+")

https://regex101.com/r/6zRLSC/1

如果您有多个单引号，则 while 循环可以解决该问题。

Answer 2

 var string = `This is an example text. I'd love to fix this. 

<a href="https://www.example.com/i'd-love-to-fly-but-don't-like-heights/"> I'd love to fly but don't like heights link </a> 

Inside the text there could be more urls 

<a href="https://www.example.com/i'd-rather/">I'd rather link</a>.`;

// While we match the pattern that we're targeting, keep on replacing

while(string.match(/(href="[^"]+)'([^"]+")/))

{

    string = string.replace(/(href="[^"]+)'([^"]+")/g, '$1$2')

}

console.log(string);