嵌套列表黑客排名测试用例python

Question

以下是我的 hackerrank 嵌套列表问题代码，用于打印学生倒数第二名的姓名。我开始了我的 Python 探索之旅。这段代码在下面列出的两个测试用例中失败了……任何人都可以帮我解决这个问题。4 索娜 -25.001 莫娜 -25.0001 迷你 -25.000 丽塔 -25.02.4 Shadab 8 Varun 8.9 Sarvesh 9.5 Harsh 10n=int(input())l=[]for i in range(n*2) :    ele=input()    l.append(ele) l2=[]for i in range(1,n*2,2) :    l2.append(l[i])l2.sort()a=min(l2)for i in range(n) :    for i in l2 :        if i == a :            l2.remove(i)b=min(l2)l3=[]for i in range(n*2) :    if l[i] == b :        l3.append((l[i-1]))l3.sort()for i in range(len(l3)) :    print(l3[i])

Answer 1

它对我有用。如果需要，您可以分配 inf 而不是 1000。

if __name__ == '__main__':

    d_list=[]

    low=[1000,1000]

    for _ in range(int(input())):

        name = input()

        val = float(input())

        if val < low[0]:

            low[1]=low[0]

            low[0]=val

        elif val < low[1] and val >low[0]:

            low[1]=val

        if val<=low[1]:

            d_list.append([name,val])

    for student in sorted(d_list):

        if student[1]==low[1]:

            print(student[0])

Answer 2

no_of_students = int(input())

records = []

for i in range(no_of_students):

    name = input()

    score = float(input())

    records.append([name, score])

records = dict(records)

scores = sorted(set(records.values()))

second_lowest_score = scores[1]

second_lowest_students = [name for name,score in records if 

score==second_lowest_score]

second_lowest_students.sort()

for name in second_lowest_students:

    print(name)

Answer 3

t = int(input())

name = []

marks = []

for i in range(t):

    n = input()

    m = input()

    name.append(n)

    marks.append(float(m))

d_marks = []

for i in range(t):

    if(marks[i] not in d_marks):

        d_marks.append(marks[i])

d_marks.sort()

s_min = float(d_marks[1])

l = []

for i in range(t):

    if(float(marks[i]) == s_min):

        l.append(name[i])

l.sort()

for i in range(len(l)):

    print(l[i])