改进代码 - 网络抓取工作机会 - 职位、雇主、薪水、需要链接

Question

我写了一个网络抓取代码，扫描工作门户中的所有页面，并在功能中报告满足薪水要求的工作机会。对我来说重要的字段是职位、雇主、薪水和链接。我现在使用的是 getText() 方法，但需要所有元素。结果看起来像：Zubný lekár/lekárka DENTAL CARE Dr. Rosa, s. r. o.Námestie sv. Františka, Karlova Ves        Od 4 500 EUR/mesiac    Pridané Pred 4 dňami  Pridať k vybraným   https://www.profesia.sk/praca/dental-care-dr-rosa/O3863429https://www.profesia.sk/praca/dental-care-dr-rosa/O3863429Head of Core Technology DevelopmentESET, spol. s r.o.Bratislava        4 500 EUR/mesiac    Pridané pred 2 týždňami  Pridať k vybraným   https://www.profesia.sk/praca/eset/C22141https://www.profesia.sk/praca/eset/O3933805https://www.profesia.sk/praca/eset/O3933805它需要两个不必要的项目并复制链接（因为 <a 'href' 中有 2 到 3 个链接）有更好的主意吗？def search4job(salary):    import bs4, requests, re    #Classes -> employer: class='employer'>    # -> salary ".label"    # -> Job Title class='title'    # -> TODO: link     base_url= 'https://www.profesia.sk/praca/bratislava/plny-uvazok/?languages=73&page_num={}'    page = 1 #to start from page1    request = requests.get(base_url.format(page)) #to take complete url    HTML = bs4.BeautifulSoup(request.text,'lxml')     pattern = r'(\d\s\d\d\d)' #salary pattern    while len(HTML.select(".list-row"))>0:         #in pages without job offer the len of list-row is 0, iterates until there are no job offers