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如何循环遍历 HTML 元素

如何循环遍历 HTML 元素

沧海一幻觉 2023-06-09 10:53:57
此代码使得当用户单击其中一种颜色 (color1-4) 时,它会设置display所有鞋子的 CSS 属性,none但单击的颜色除外,其display设置为block. 代码看起来很脏,雇主不会批准。我将如何着手制作一个 for 循环,或者以其他方式使代码更清晰?color2.addEventListener('click', () => {    shoe.style.display = "none";    shoe3.style.display = "none";    shoe5.style.display = "none";    shoe2.style.display = "block";    console.log('u removed it and added another');});color3.addEventListener('click', () => {    shoe.style.display = "none";    shoe3.style.display = "none";    shoe5.style.display = "none";    shoe2.style.display = "none";    shoe3.style.display = "block";    console.log('u removed it and added another');});color4.addEventListener('click', () => {    shoe.style.display = "none";    shoe3.style.display = "none";    shoe5.style.display = "none";    shoe3.style.display = "none";    shoe5.style.display = "block";    console.log('u removed it and added another');});color1.addEventListener('click', () => {    shoe.style.display = "block";    shoe2.style.display = "none";    shoe3.style.display = "none";    shoe4.style.display = "none";    shoe5.style.display = "none";    console.log('u removed it and added another');});color2.addEventListener('click', () => {    shoe.style.display = "none";    shoe3.style.display = "none";    shoe5.style.display = "none";    shoe2.style.display = "block";    console.log('u removed it and added another');});
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3 回答

?
繁花不似锦

TA贡献1851条经验 获得超4个赞

您需要使用 Array 和自定义函数来操作 DOM 元素,这是一个基本示例:


var shoes = [s1,s2,s3]; //DOM element arrays

colorShoe = (shoe) =>{

  for(let i=0; i<shoes.length;i++){

    if(shoes[i] === shoe){

      //Handling style

    }

}


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反对 回复 2023-06-09
?
慕桂英546537

TA贡献1848条经验 获得超10个赞

如果你不想使用 array ,你可以这样做。只需使用 window['var name'+the index number] 然后你可以在后面添加你想做的事情 :D 谢谢 :D


color3.addEventListener('click', () => {

        for (var i = 1; i <= 5; i++) {

            if (i == 3) shoe.style.display = "block";

            else {

                window['shoe'+i].style.display = "none";

            }

        }

        console.log('u removed it and added another');

    });


    color4.addEventListener('click', () => {

        for (var i = 1; i <= 5; i++) {

            if (i == 4) shoe.style.display = "block";

            else {

                window['shoe'+i].style.display = "none";

            }

        }

        console.log('u removed it and added another');

    });


    color1.addEventListener('click', () => {

        for (var i = 1; i <= 5; i++) {

            if (i == 1) shoe.style.display = "block";

            else {

                window['shoe'+i].style.display = "none";

            }

        }

        console.log('u removed it and added another');

    });


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反对 回复 2023-06-09
?
宝慕林4294392

TA贡献2021条经验 获得超8个赞

请检查一下,看看您是否可以像下面这样修改您的代码:


const colorList = [color1, color2, color3]; // you can add more

const shoeList = [shoe1, shoe2, shoe3]; // you can add more

[color1, color2, color3].forEach((color, colorIndex) => {

  color.addEventListener('click', () => {

    shoeList.forEach((shoe, shoeIndex) => {

      if (colorIndex === shoeIndex) {

        shoe.style.display = "block";

      } else {

        shoe.style.display = "none";

      }

    });

  });

});


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反对 回复 2023-06-09
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