使用 JSON-B 反序列化 JSON 数组

Question

我正在尝试使用 JSONB 反序列化 JSON 数组。JSON[  {    "id": "1",    "animal": "dog",    "age": "3"  },  {    "id": "2",    "animal": "cat",    "age": "5"  }]控制器Jsonb jsonb = JsonbBuilder.create();    Animal animal;AnimalsList animalsList;public AnimalsList getAnimals() {    try {        animalsList = jsonb.fromJson("[{\"id\":\"1\",\"animal\":\"dog\",\"age\":\"3\"},{\"id\":\"2\",\"animal\":\"cat\",\"age\":\"5\"}]", AnimalsList.class);    } catch (JSONException ex) {        Logger.getLogger(Controller.class.getName()).log(Level.SEVERE, null, ex);    }    return animalsList;}动物清单public class AnimalsList implements Serializable{    private List<Animal> list;    public AnimalsList() {    }    public AnimalsList(List<Animal> list) {        this.list = list;    }    // getter & setter}动物public class Animal implements Serializable{    private int id;    private String animal;    private int age;    public Animal() {    }    public Animal(int id, String animal, int age) {        this.id = id;        this.animal = animal;        this.age = age;    }    // getter & setter}但我收到以下错误：javax.json.bind.JsonbException: Can't deserialize JSON array into: class com.model.AnimalsList

Answer 1

List<Dog> dogs = new ArrayList<>();

dogs.add(falco);

dogs.add(cassidy);

// Create Jsonb and serialize

Jsonb jsonb = JsonbBuilder.create();

String result = jsonb.toJson(dogs);

// Deserialize back

dogs = jsonb.fromJson(result, new ArrayList<Dog>(){}.getClass().getGenericSuperclass());

Answer 2

如果您不限于仅使用 JSON-B，则可以通过 TypeReferencing 使用 ObjectMapper 来完成。

private ObjectMapper objectMapper = new ObjectMapper();

List<Animal> animals = objectMapper.readValue(json , new TypeReference<List<Animal>>(){});