正则表达式无法在换行后捕获字符串

Question

我有一个字符串，我试图将其拆分为更小的字符串d+\/（任意数字后跟 a /）。这是我的字符串：2/  This is a string that has some words on a new line3/ This is another string that might also have some words on a new line到目前为止，我正在使用这段代码：$re = '/\d+\/\s+.*/';$str = '2/  This is a string that has some words on a new line3/ This is another string that might also have some words on a new line';preg_match_all($re, $str, $matches, PREG_SET_ORDER, 0);但问题是，对于第一场比赛，我只得到第一行：[Match 1] 2/  This is a string[Match 2] 3/ This is another string that might also have some words on a new line我怎样才能让所有的行都匹配到d+\/或直到整个字符串/文本的末尾？期望的结果：[Match 1] 2/  This is a string that has some words on a new line[Match 2] 3/ This is another string that might also have some words on a new line

Answer 1

分裂与'~(?=\d+/)~'。任何功能都使用 preg_split mebe。

更新：不建议使用 split 提取记录，
因为第一个元素不是记录，而是必须转置的垃圾。
仅使用断言进行拆分也很慢，就像看着油漆变干一样。
谁将此标记为 split 的副本以获取记录，谁就错了！
如果按照这个逻辑，成千上万的问题都是分裂的重复，
所以管理员编辑他们的数据库的时间，或者我们是无缘无故的选择？

推荐/首选/明智的方法是将所有
记录与此严格匹配(?s)\d+/.*?(?=\d+/|$)

演示

演示包含对正则表达式的 funcshun 的评论。