2 回答
TA贡献1825条经验 获得超6个赞
从点击处理程序中的按钮移除焦点可能是最优雅的方法:e.target.blur()
。它适用于任何 HTML 元素,无论它是否可聚焦(与div
您的情况一样)。
const myArray = [
'Alex',
'Bob',
'Charlie',
'Dennis',
'Evan',
'Floron',
'Gorgious',
'Harris',
'Ivan',
'Jennis',
'Kurber',
'Lowrance',
]
const ExpandList = (props) => {
const [idx, setIdx] = React.useState(8)
const handleExpand = e => {
e.target.blur()
setIdx(idx + 1)
}
return <div className='demo'>
<h1>Name List</h1>
{myArray.slice(0,idx).map(
name => <p key={name}>{name}</p>
)}
<div>
<button onClick={handleExpand} children='Button Expand' className='pointer' />
<div onClick={handleExpand} className='pointer'>Div Expand</div>
</div>
</div>
}
ReactDOM.render(<ExpandList/>, document.getElementById('root'))
.demo>p {
display: block;
padding: 20px;
color: #666;
background: #3331;
}
.demo>div>div {
display: flex;
padding: 15px;
margin-left: auto;
color: #666;
background: #3331;
}
.pointer {
cursor: pointer;
}
.pointer:hover {
background-color: #6663;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/16.14.0/umd/react.production.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/16.14.0/umd/react-dom.production.min.js"></script>
<div id='root' class='demo'>hello</div>
TA贡献1875条经验 获得超5个赞
单击后暂时卸载按钮并设置超时以将其添加回来似乎可以完成工作。由于浏览器失去了对原始展开按钮的关注,这将在不关注原始按钮的情况下保持内容刷新:
const ExpandList = (props) => {
const [idx, setIdx] = React.useState(8)
const [showBtn, setShowBtn] = React.useState(true)
const handleExpand = e => {
setShowBtn(false)
setIdx(idx + 1)
setTimeout(() => setShowBtn(true), 10)
}
return <div className='demo'>
<h1>Name List</h1>
{myArray.slice(0,idx).map(
name => <p key={name}>{name}</p>
)}
{showBtn?
<div>
<button onClick={handleExpand} children='Button Expand' className='pointer' />
<div onClick={handleExpand} className='pointer'>Div Expand</div>
</div> :
<div></div>
}
</div>
}
但我仍在寻找一种不需要“卸载”应该一直存在的东西的方法。
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