JavaScript 对数组的数组进行排序

Question

我想根据数组对数组数组进行排序，然后按数组中项目的长度进行排序。采用以下主排序数组：const key = [  "meraki",  "gsuite",  "active directory",  "sophos",  "manageengine"]我想采用类似于以下内容的数组：const raw = [  ["manageengine"],  ["sophos"],  ["active directory"],  ["gsuite"],  ["meraki"],  ["sophos", "manageengine"],  ["active directory", "sophos"],  ["active directory", "manageengine"],  ["gsuite", "active directory"],  ["gsuite", "sophos"],  ["gsuite", "manageengine"],  ["meraki", "gsuite"],  ["meraki", "active directory"],  ["meraki", "sophos"],  ["meraki", "manageengine"],  ["active directory", "sophos", "manageengine"],  ["gsuite", "active directory", "sophos"],  ["gsuite", "active directory", "manageengine"],  ["gsuite", "sophos", "manageengine"],  ["meraki", "gsuite", "active directory"],  ["meraki", "gsuite", "sophos"],  ["meraki", "active directory", "sophos"],  ["meraki", "gsuite", "manageengine"],  ["meraki", "active directory", "manageengine"],  ["meraki", "sophos", "manageengine"],  ["gsuite", "active directory", "sophos", "manageengine"],  ["meraki", "gsuite", "active directory", "sophos"],  ["meraki", "gsuite", "active directory", "manageengine"],  ["meraki", "gsuite", "sophos", "manageengine"],  ["meraki", "active directory", "sophos", "manageengine"],  ["meraki", "gsuite", "active directory", "sophos", "manageengine"]];在上面的示例中，我希望raw根据key数组中的每个项目对数组进行排序。我的第一次尝试是做类似的事情：const result = [];for (const name of result) {  const sorted = keys.filter((s) => s[0] === name);  result.push(...sorted);}result.sort((a, b) => a.length - b.length);但是，这只考虑了数组中的第一项，而不考虑其余项的排序。

Answer 1

要排序，您必须首先检查长度。如果两者相等，我们必须检查a/b中第一个元素的索引位置key。如果它们相同，则继续移动到两个数组中的下一个元素。

这个答案利用了0一个虚假价值的事实。例子是：0 || -1 //=> -1和1 || -1 //=> 1

const key = ["meraki", "active directory", "sophos"];

const raw = [

  ["meraki"],

  ["active directory"],

  ["sophos", "active directory"],

  ["active directory", "sophos"],

  ["sophos"],

  ["meraki", "active directory", "sophos"],

];

raw.sort((a, b) => (

  a.length - b.length || a.reduce((diff, _, i) => (

    diff || key.indexOf(a[i]) - key.indexOf(b[i])

  ), 0)

));

console.log(raw);

console.table(raw); // check browser console

Answer 2

考虑以下方法

const key = [

  "meraki",

  "active directory",

  "sophos"

]

const raw = [

   ["sophos"],

   ["meraki"],

   ["active directory"],

   ["sophos", "active directory"],

   ["active directory", "sophos"],

   ["meraki", "active directory", "sophos"]

]

const compareThis = (a, b) => {

  if (a.length !== b.length) {

    return a.length - b.length

  }

  let itemFound = 0;

  for (let keyIndex in key) {

    for (let aIndex in a ) {

      if(a[aIndex] === key[keyIndex]) {

        itemFound = -1;

        break;

      }

      if(b[aIndex] === key[keyIndex]) {

        itemFound = 1;

        break;

      }

    }

    if(itemFound !== 0) { break }

  }

  return itemFound;

}

const sortedData = raw.sort(compareThis)

console.log(sortedData)