我花了很长时间才让它返回一个结果,但现在我只能让这个函数返回我数组中的第一个结果。示例 JSON:(下一个函数的 JSON.stringify(mapResult) 的输出)[ [ { "_attributes": { "key": "aed8d486-9557-4e53-ae9c-78bfc938c719", "number": "1", "type": "Video", "title": "Stars.mov", "shortTitle": "Stars.mov", "state": "Completed", "position": "119980", "duration": "119980", "loop": "False", "muted": "True", "volume": "100", "balance": "0", "solo": "False", "audiobusses": "M", "meterF1": "0", "meterF2": "0" }, "_text": "Stars.mov" }, { "_attributes": { "key": "b9be415e-1c63-47fb-9791-72432eccd0c3", "number": "2", "type": "Colour", "title": "Colour", "shortTitle": "Colour", "state": "Paused", "position": "0", "duration": "0", "loop": "False" }, "_text": "Colour" }, { "_attributes": { "key": "23d74bb3-dbd8-410d-8b16-d05a9db4b656", "number": "3", "type": "Capture", "title": "Sample Input", "shortTitle": "Sample Input", "state": "Running", "position": "0", "duration": "0", "loop": "False", "muted": "True", "volume": "100", "balance": "0", "solo": "False", "audiobusses": "M", "meterF1": "0", "meterF2": "0" }, "_text": "Sample Input" } ]]
1 回答
Helenr
TA贡献1780条经验 获得超4个赞
您在另一个数组中有一个数组。这就是为什么您的 map 函数只返回一个元素的原因。像这样重写你的代码......
const modifiedMap = mapResulst[0];
let inputMap = []
if(modifiedMap){
inputMap = modifiedMap.map((input, i) => {
return (
<div key={i}>
<h3>{input._attributes.title}</h3>
<span>
<Button color="danger" size="lg" block>
{input._attributes.number}<br />
{input._attributes.title}<br />
State: {input._attributes.state}<br />
Loop: {input._attributes.loop}<br />
Type: {input._attributes.type}<br />
</Button>
</span>
</div>
)
})
}
return inputMap
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