4 回答
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TA贡献1891条经验 获得超3个赞
eacha是在下一次迭代中取下一个值的循环变量。将转换后的值存储在另一个列表中。
a = ['3.465759','2.8797','9.23544']
b = []
for each in a:
print(each)
each = round(float(each),3) + 2
b.append(each)
print(b)
输出:
3.465759
2.8797
9.23544
[5.466, 4.88, 11.235]
或者
如果你想就地修改列表,那么
a = ['3.465759','2.8797','9.23544']
for i in range(len(a)):
each = a[i]
print(each)
each = round(float(each),3) + 2
a[i] = each
print(a)
或者
使用列表理解
[round(float(each),3) + 2 for each in a]
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TA贡献1785条经验 获得超4个赞
您可以使用地图:
a = ['3.465759','2.8797','9.23544'] float_list = list(map(float, a)) print(float_list)
输出:
[3.465759, 2.8797, 9.23544]
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TA贡献1803条经验 获得超6个赞
a = ['3.465759','2.8797','9.23544']
result = []
for each in a:
each = round(float(each),3) + 2
result.append(each)
print(result)
Output: [5.466, 4.88, 11.235]
这是你想要的?
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TA贡献1804条经验 获得超2个赞
你没有改变a,当你进行转换时,请确保更改值:即:
a = ['3.465759','2.8797','9.23544']
for i in range(len(a)):
each = a[i]
print(each)
each = round(float(each),3) + 2
a[i] = each
print(a)
或者
a = ['3.465759','2.8797','9.23544']
for i, each in enumerate(a):
print(each)
each = round(float(each),3) + 2
a[i] = each
print(a)
3.465759
2.8797
9.23544
[5.466, 4.88, 11.235]
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