我正在处理大量图像并尝试搜索 jpeg,然后将它们的路径写入文件。目前,我可以找到我想要的所有 jpeg。但是,我的“索引”文件中的每个新路径都会覆盖最后一个。因此,它根本不是一个索引/列表,而是一个包含 a/path/to/just/one/file.jpg 的文本文件我简化了我的代码并在下面添加了它。它很冗长,但这是为了我的阅读利益以及其他像我这样的新手。#----------#-->Import Modules#I'm pretty sure there is redundancy here and it's not well laid out#but I'm new to coding and it worksimport osimport pathlibimport glob, osfrom pathlib import Pathimport os.pathfrom os import path#----------#-->Global Vars#Simplified example of my variablesworking_dir = "/Users/myname/path/to/working dir"records_dir = str(working_dir + "/Records")#----------#-->Search Location#Define where the jpeg search is to take place#(actually dictated via user input, Minecraft is just an example)search_locations = ["/Users/myname/minecraft"]#---------#--> Search for jpgs and write their paths to a file#define the file where the jpeg paths are to be stored,#(I'm referring to the storage file as an index of sorts)jpg_index = str(records_dir + "/index_for_all_jpgs")#Its embedded in a forloop because the user can add multiple locationsfor search_location in search_locations: #get the desired paths from the search location for path in Path(search_location).rglob('*.jpg'): #Open the index where paths are to be stored with open(jpg_index, 'w') as filehandle: #This is supposed to write each paths as a new line #But it doesn't work filehandle.writelines('%s\n' % path)我也尝试过使用更简单的想法;filehandle.write(path)还有一个我不完全理解的更复杂的;filehandle.writelines("%s\n" % path for path in search_location)然而,我所做的一切都以稍微不同的方式失败了。
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梦里花落0921
TA贡献1772条经验 获得超6个赞
'w' 选项告诉 open() 方法覆盖 jpg_index 文件中以前的任何内容。因为每次在写入 jpeg 路径之前调用此方法,所以只剩下最后一个。使用“a”(附加)代替“w”(写入)来告诉 open() 方法附加到文件而不是每次都覆盖它。
例如:
for search_location in search_locations:
for path in Path(search_location).rglob('*.jpg'):
with open(jpg_index, 'a') as filehandle:
filehandle.writelines('%s\n' % path)
或者,您可以将 with... as 语句移到 for 循环之外。这样,jpg_index 文件只会在开始时打开并覆盖一次,而不是在其中已经有信息之后。
例如:
with open(jpg_index, 'w') as filehandle:
for search_location in search_locations:
for path in Path(search_location).rglob('*.jpg'):
filehandle.writelines('%s\n' % path)
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