通过分隔符扩展一串切片

Question

我想通过分隔符“/”扩展一串切片。例如，扩展以下切片s := []string{"5/3","9","5/4/1","6"}应该产生单独的切片：["5","9","5","6"] ["5","9","4","6"] ["5","9","1","6"]["3","9","5","6"] ["3","9","4","6"] ["3","9","1","6"]我几乎被困在这里var c [][]string{}s := []string{"5/3","9","5/4/1","6"}for _, v := range s {    combos := strings.Split(v, "/")    for _, combo := range combos {    }       }

Answer 1

除了运行时间，您可以通过递归来实现。

func Perm(digits [][]string) (perm [][]string) {

    if len(digits) == 0 || len(digits) == 1 {

        return digits

    }

    nextDigits := Perm(digits[1:])

    for _, digit := range digits[0] {

        for _, next := range nextDigits {

            cat := append([]string{digit}, next...)

            perm = append(perm, cat)

        }

    }

    return perm

}

操场