如何使用 Go map 创建对象的 JSON 数组？

Question

我需要使用地图创建一个 JSON 数组。package mainimport "fmt"func main(){    id := [5]string{"1","2","3","4","5"}    name := [5]string{"A","B","C","D","E"}    parseData := make(map[string]string)    for counter,_ := range id {        parseData["id"] = id[counter]        parseData["name"] = name[counter]        fmt.Println(parseData)    }}我目前的输出：map[id:1 name:A]map[id:2 name:B]map[id:3 name:C]map[id:4 name:D]map[id:5 name:E]我需要如下所示的 JSON 输出：[{id:1, name:A},{id:2, name:B},{id:3, name:C},{id:4, name:D},{id:5, name:E}]我知道使用 map 的基础知识它是用于键：值对的字典。如何使用 map 实现 JSON 输出。

Answer 1

要创建 through map 数组JSON，您需要创建一个map作为slice单个 map 而另一个只是单个 map，然后在单个 map 中一个一个地赋值，然后将其附加到 slice of map 中，如下面的代码所示：

package main

import (

    "fmt"

    "encoding/json"

)

func main(){

    id := [5]string{"1","2","3","4","5"}

    name := [5]string{"A","B","C","D","E"}

    parseData := make([]map[string]interface{}, 0, 0)

    for counter,_ := range id {

        var singleMap = make(map[string]interface{})

        singleMap["id"] = id[counter]

        singleMap["name"] = name[counter]

        parseData = append(parseData, singleMap)

    }

    b, _:= json.Marshal(parseData)

    fmt.Println(string(b))

}

你也可以在这里测试

它打印JSON为：

[{"id":"1","name":"A"},

{"id":"2","name":"B"},

{"id":"3","name":"C"},

{"id":"4","name":"D"},

{"id":"5","name":"E"}]

Answer 2

对我来说，这更像是一组对象。您可以像这样获得所需的输出：

type data struct {

    Id string

    Name string

}

func main(){

    id := [5]string{"1","2","3","4","5"}

    name := [5]string{"A","B","C","D","E"}

    var parsedData []data

    for counter := range id {

        parsedData = append(parsedData, data{Name: name[counter], Id: id[counter]})

    }

    bytes, _ := json.Marshal(parsedData)

    fmt.Print(string(bytes))

}

输出应如下所示：

[

 {"Id":"1","Name":"A"},

 {"Id":"2","Name":"B"},

 {"Id":"3","Name":"C"},

 {"Id":"4","Name":"D"},

 {"Id":"5","Name":"E"}

]