如何用数组的另一个值替换javascript中数组的值？

Question

我正在尝试用另一个数组替换字符串中存在的数组中的值。在 Javascript 中执行此操作的最佳方法是什么？这是我的代码：var string = "I've to but the Item1 along with Item2 and Item3. From the Item4."var array1 = ['Item1', 'Item2', 'Item3', 'Item4']var array2 = ['Product1', 'Product2', 'Product3', 'Product4']输出应该是这样的var replaced = "I've to but the Product1 along with Product2 and Product3. From the Product4."两个数组中的每个值都完全不同。

Answer 1

您可以使用String.prototype.replaceAll替换字符串

const input = "I've to but the Item1 along with Item2 and Item3. From the Item4.";

const original = ['Item1', 'Item2', 'Item3', 'Item4'];

const target = ['Product1', 'Product2', 'Product3', 'Product4'];

let result = input;

original.forEach((item, index) => {

  result = result.replaceAll(item, target[index]);

});

console.log(result);

Answer 2

我希望我有所帮助。

var array1 = ['Item1', 'Item2', 'Item3', 'Item4'];

var array2 = ['Product1', 'Product2', 'Product3', 'Product4'];

var string = "I've to but the Item1 along with Item2 and Item3. From the Item4.";

for (var i = 0; i < array1.length; i++) {

    var string = string.replace(array1[i], array2[i]);

}

console.log(string);

Answer 3

您可以使用模板文字，例如

var array1 = [Item1, Item2, Item3, Item4];

var array2 = [Product1, Product2, Product3, Product4]

var string = `I've to but the ${array1[0]} along with ${array1[1]} and ${array1[2]}. From the 

${array1[3]}.`

var replaced = `I've to but the ${array2[0]} along with ${array2[1]} and ${array2[2]}. 

From the ${array2[3]}.`