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发展一个 for 循环以跳过不等于的字典键和值

发展一个 for 循环以跳过不等于的字典键和值

哔哔one 2023-05-09 10:42:49
背景我的结构如下:trash = [ {'href': 'https://www.simplyrecipes.com/recipes/cuisine/portuguese/'},          {'href': 'https://www.simplyrecipes.com/recipes/cuisine/german/'},          {'href': 'https://www.simplyrecipes.com/recipes/season/seasonal_favorites_spring/'},          {'href': 'https://www.simplyrecipes.com/recipes/type/condiment/'},          {'href': 'https://www.simplyrecipes.com/recipes/ingredient/adobado/'}]          {'href': 'https://www.simplyrecipes.com/',           'title': 'Simply Recipes Food and Cooking Blog', 'rel': ['home']},]如您所见,大多数键是'href',大多数值包含'https://www.simplyrecipes.com/recipes/'. 问题是那些不符合此命名约定的键和值......代码:此代码遍历结构并使用re.findall获取之间的字符串值'recipes/',然后继续/为其对应的值创建一个新的键名。for x in trash:    for y in x.values():        txt = ''        for i in re.findall("recipes/.*", y):            txt += i            title = txt.split('/')[1]            print({title: y})输出:假设我删除了不符合被命名和包含代码字符串值的命名约定的keys和,如下所示:values'href''https://www.simplyrecipes.com/recipes/'{'cuisine': 'https://www.simplyrecipes.com/recipes/cuisine/portuguese/'}{'cuisine': 'https://www.simplyrecipes.com/recipes/cuisine/german/'}{'season': 'https://www.simplyrecipes.com/recipes/season/seasonal_favorites_spring/'}{'type': 'https://www.simplyrecipes.com/recipes/type/condiment/'}{'ingredient': 'https://www.simplyrecipes.com/recipes/ingredient/adobado/'}问题:代码的问题是,TypeError: expected string or bytes-like object如果结构的键和值不符合代码中的命名约定,我会得到一个。问题:我将如何改进这段代码,以便它跳过任何未命名的键'href',如果它们被命名'href',如果它们的值不包含,将跳过'https://www.simplyrecipes.com/recipes/'?
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for d in trash:

    for key, value in d.items():

        if key != "href" or "https://www.simplyrecipes.com/recipes/" not in value:

            continue  # Move onto next iteration

        txt = ''

        for i in re.findall("recipes/.*", value):

            txt += i

            title = txt.split('/')[1]

            print({title: value})

您可以使用 迭代字典的键和值dict.items()。然后你可以使用if语句来检查你的条件,continue如果他们不满足。


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反对 回复 2023-05-09
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