对元组（int，字符串）进行排序并将字符串值保存在字符串数组中

Question

我正在使用此代码对单词和整数对进行排序，按整数对对进行排序（降序）对元组进行排序后，如何仅将字符串值保存在 String [] 数组中？我在这里找到了代码，因为我是新来的，所以我无法在同一页面上发表评论。（@Elliott Frisch）如何按频率对单词进行排序 public Tuple(int count, String word) {    this.count = count;    this.word = word;}@Overridepublic int compareTo(Tuple o) {    return new Integer(this.count).compareTo(o.count);}public String toString() {    return word + " " + count;}}public static void main(String[] args) {String[] words = { "the", "he", "he", "he", "he", "he", "he", "he",        "he", "the", "the", "with", "with", "with", "with", "with",        "with", "with" };// find frequenciesArrays.sort(words);Map<String, Integer> map = new HashMap<String, Integer>();for (String s : words) {    if (map.containsKey(s)) {        map.put(s, map.get(s) + 1);    } else {        map.put(s, 1);    }}List<Tuple> al = new ArrayList<Tuple>();for (Map.Entry<String, Integer> entry : map.entrySet()) {    al.add(new Tuple(entry.getValue(), entry.getKey()));}Collections.sort(al);System.out.println(al);}

Answer 1

如果它必须是数组，你去：

        Collections.sort(al);

        String[] wordsResult = new String[al.size()];

        int i = 0;

        for (Tuple tuple : al) {

            wordsResult[i++] = tuple.word;

        }

        Stream.of(wordsResult).forEach(System.out::println);

        System.out.println(al);

Answer 2

您还可以使用 Stream-API 对这个 ArrayList 进行排序

 Object[] arr = al.stream()

.sorted(Comparator.comparing(Tuple::getCount).reversed())//sort counts as per count

.map(Tuple::getWord) //mapping to each count to word

.toArray(); //collect all words to array

 System.out.println(Arrays.toString(arr));

你也可以把这些话收藏起来List<String>

List<String> arr =al.stream() 

.sorted(Comparator.comparing(Tuple::getCount).reversed())//sort counts as per count

.map(Tuple::getWord) //mapping to each count to word

.collect(Collectors.toList())//Collect to List