将另一个对象传递给当前的休息服务不会抛出异常

Question

这是与其他服务兼容的休息请求：{  "fromDate": 1562773101000,  "toDate": 1563118701000,  "turnOverType": 4,  "fromAmount": 1,  "toAmount": 10000000,  "voucherDescription": null,  "articleDescription": null,  "referenceNumbers": [],  "offset": 3,  "pageSize": 20,  "iban": "BLAHBLAHBLAHBLAH"}这是与请求不匹配的对应模型：@XmlAccessorType(XmlAccessType.FIELD)public class TransferRequestInquiryFilter implements Serializable {    @XmlElement(name = "sourceIbans")    private List<String> sourceIbans;    @XmlElement(name = "transferType")    private TransferType transferType;    @XmlElement(name = "fromTransferDate")    private Timestamp fromTransferDate;    @XmlElement(name = "toTransferDate")    private Timestamp toTransferDate;    @XmlElement(name = "fromRegistrationDate")    private Timestamp fromRegistrationDate;    @XmlElement(name = "toRegistrationDate")    private Timestamp toRegistrationDate;    @XmlElement(name = "trackingNumbers")    private List<String> trackingNumbers;    @XmlElement(name = "referenceNumbers")    private List<String> referenceNumbers;    @XmlElement(name = "transactionIds")    private List<String> transactionIds;    @XmlElement(name = "status")    private TransactionStatus status;    @XmlElement(name = "fromAmount")    private Long fromAmount;    @XmlElement(name = "toAmount")    private Long toAmount;    @XmlElement(name = "destinationIbans")    private List<String> destinationIbans;}只是 fromAmount 和 toAmount 填充。但我想为这种情况获得一个例外，并向客户提出一个错误的请求。我怎样才能做到这一点？如果我在 rest 请求和 model 之间遇到名称冲突或类型冲突，我需要处理它并向客户发出错误的请求。我正在使用 spring mvc 5 和 jackson-core 以及 jackson-databind 2.9.4

Answer 1

@validated使用 validation-api，为字段和before 控制器方法注释正确的验证，并使用@validbeforeRequestBody对象将抛出正确的验证异常。