Python - 如何在字典中获取具有相同值的键/

Question

我有一个字典：{'Key_1': ['Value_1'], 'Key_2': ['Value_1', 'Value_2'], 'Key_3': ['Value_2'], 'Key_4': ['Value_3']}我想获得具有相同值的键，例如，输出如下：Key_1 and Key_2 have same Value_1Key_2 and Key_3 have same Value_2我试过这个来获得共同的价值观：list_1 = []output = []for value in dictionary.values():    for x in value:         if x in list_1:            if not x in output:                output.append(x)         else:             list_1.append(x)有了这个，我得到了共同的价值，但没有相应的键。

Answer 1

d = {'Key_1': ['Value_1'], 'Key_2': ['Value_1', 'Value_2'], 'Key_3': ['Value_2'], 'Key_4': ['Value_3']}

out = {}

for k, v in d.items():

    for vv in v:

        out.setdefault(vv, []).append(k)

for k, v in out.items():

    if len(v) > 1:

        print('{} have same {}'.format(' and '.join(v), k))

印刷：

Key_1 and Key_2 have same Value_1

Key_2 and Key_3 have same Value_2