访问 JSON 对象的键值

Question

我卡住了。看起来这应该有效，但事实并非如此。我正在尝试访问对象的键值，但它不起作用。我以前做过这个，并且在堆栈溢出和其他地方阅读了很多东西，但它仍然不起作用。这是我的代码：  var validate = UrlFetchApp.fetch(url, options);    Logger.log('validate = ' + validate);  Logger.log("validate['response'] = " + validate["response"]);  Logger.log('validate.response = ' + validate.response);  Logger.log("validate.['done'] = " + validate["done"]);  Logger.log("validate.done = " + validate.done);    var validateObj = JSON.stringify(JSON.parse(validate));    Logger.log("validateObj = " + validateObj);  Logger.log("validateObj.response = " + validateObj.response);  Logger.log("validateObj.done = " + validateObj.done);这是日志：validate = {  "done": true,  "response": {    "@type": "type.googleapis.com/google.apps.script.v1.ExecutionResponse",    "result": "Invalid Full Name.  Please enter a valid Full Name."  }}validate['response'] = undefinedvalidate.response = undefinedvalidate.['done'] = undefinedvalidate.done = undefinedvalidateObj = {"done":true,"response":{"@type":"type.googleapis.com/google.apps.script.v1.ExecutionResponse","result":"Invalid Full Name.  Please enter a valid Full Name."}}validateObj.response = undefinedvalidateObj.done = undefined使用括号表示法时，我也尝试过使用单引号和双引号。谁能帮我看看错误？

Answer 1

您正在尝试从字符串访问responseand属性，因此您得到了. 您已尝试对响应执行操作，但随后返回到字符串，只需执行并访问该属性doneundefinedJSON.parseJSON.stringifyJSON.parse

var validateObj = JSON.parse(validate); // Now you have a deserialized object

Logger.log("validateObj = " + validateObj); // You should get "validateObj = [object Object]"

Logger.log("validateObj.response = " + validateObj.response);

Logger.log("validateObj.done = " + validateObj.done);

Logger.log("validateObj[ 'response' ] = " + validateObj[ 'response' ] );

Logger.log("validateObj[ 'done' ]= " + validateObj[ 'done' ]);