如何过滤和查找对象内部

Question

我想在 branches 数组中搜索 finder 对象，如果找到匹配项，那么我想获取 finder 对象的位置名称。var branches= [  {    locationName: "Cool Towers",    coordinates: [      {        latitude: 25.33853805869942,        longitude: 55.393801012135796,      },      {        latitude: 25.33848836326937,        longitude: 55.393874772883706,      },      {        latitude: 25.338230189121408,        longitude: 55.39362935075884,      }    ],  },  {    locationName:"Great Towers",    coordinates: [      {        latitude: 25.16626719853835,        longitude: 55.26170584184425,      },      {        latitude: 25.166607063076132,        longitude: 55.26206257564323,      }    ],  }]var finder =   {        latitude: 25.166607063076132,        longitude: 55.26206257564323,  }本案例预期结果为：Great Towers这就是我尝试过的。但这总是给我第一个位置名称const filter = Object.entries(finder),  result = branches    .filter(({ coordinates }) =>      filt.every(([key, value]) => coordinates[key] === value)    )    .map(({ locationName }) => locationName);

Answer 1

这将找到坐标等于的分支finder

var branches = [

  {

locationName: "Cool Towers",

coordinates: [

  {

    latitude: 25.33853805869942,

    longitude: 55.393801012135796,

  },

  {

    latitude: 25.33848836326937,

    longitude: 55.393874772883706,

  },

  {

    latitude: 25.338230189121408,

    longitude: 55.39362935075884,

  }

],

  },

  {

locationName:"Great Towers",

coordinates: [

  {

    latitude: 25.16626719853835,

    longitude: 55.26170584184425,

  },

  {

    latitude: 25.166607063076132,

    longitude: 55.26206257564323,

  }

],

  }

];

var finder = {

latitude: 25.166607063076132,

longitude: 55.26206257564323,

}

var branch = branches.find(branch => {

return branch.coordinates.find(coordinate => {

    return coordinate.latitude == finder.latitude && 

           coordinate.longitude == finder.longitude

})

});

console.log(branch.locationName)

Answer 2

您可以使用find来实现您想要做的事情：

const match = branches.find((branch) => {

  return branch.coordinates.find((coords) => {

    return finder.longitude === coords.longitude && finder.latitude === coords.latitude

  });

});

Answer 3

您可以使用Array.find和Array.findIndex来完成

const branches = [

  {

    locationName: "Cool Towers",

    coordinates: [

      {

        latitude: 25.33853805869942,

        longitude: 55.393801012135796,

      },

      {

        latitude: 25.33848836326937,

        longitude: 55.393874772883706,

      },

      {

        latitude: 25.338230189121408,

        longitude: 55.39362935075884,

      }

    ],

  },

  {

    locationName:"Great Towers",

    coordinates: [

      {

        latitude: 25.16626719853835,

        longitude: 55.26170584184425,

      },

      {

        latitude: 25.166607063076132,

        longitude: 55.26206257564323,

      }

    ],

  }

];

const finder = {

  latitude: 25.166607063076132,

  longitude: 55.26206257564323

};

const findCoordinate = (co) => {

  return (co.latitude === finder.latitude) && (co.longitude === finder.longitude);

}

const branch = branches.find((item) => item.coordinates.findIndex(findCoordinate) >= 0);

if (branch) {

  console.log(branch.locationName);

} else {

  // Not found

}

Answer 4

let result;

for(let i = 0; i < branches.length; i++) {

    if (branches[i].coordinates.findIndex(coord => coord.latitude === finder.latitude && coord.longitude === finder.longitude) >= 0 ) {

      result = branches[i].locationName;

      break;

    }  

}

console.log(result);