我遇到了一个问题,即返回的整数值与一组相同,即使在 go 子例程中更新了值之后也是如此。我似乎无法弄清楚出了什么问题。//HostUptimeReporter - structtype HostUptimeReporter struct { updateInterval int uptime int shutdownSignal chan bool}//NewHostUpTimeReporter - create reporter instancefunc NewHostUpTimeReporter(updateIntervalInSeconds int) HostUptimeReporter { instance := HostUptimeReporter{updateInterval: updateIntervalInSeconds, shutdownSignal: make(chan bool), uptime:59} ticker := time.NewTicker(time.Duration(updateIntervalInSeconds) * time.Second) go func() { for { select { case <-ticker.C: instance.uptime += updateIntervalInSeconds fmt.Printf("updated uptime:%v\n", instance.uptime) case <-instance.shutdownSignal: ticker.Stop() return } } }() return instance}//Shutdown - shuts down the go routinefunc (hupr *HostUptimeReporter) Shutdown(){ hupr.shutdownSignal <- true}func main() { hurp := NewHostUpTimeReporter(2) defer hurp.Shutdown() fmt.Printf("current uptime:%v\n", hurp.uptime) time.Sleep(3*time.Second) fmt.Printf("new uptime:%v\n", hurp.uptime)}https://play.golang.org/p/ODjSBb0YugK任何指针表示赞赏。
1 回答
慕村9548890
TA贡献1884条经验 获得超4个赞
启动 goroutine 的函数返回一个HostUptimeReporter:
func NewHostUpTimeReporter(updateIntervalInSeconds int) HostUptimeReporter {
像这样返回一个完整的结构会返回该结构的副本,因此 goroutine 和调用NewHostUpTimeReporter者正在查看不同的东西。你想返回一个指针以便他们共享数据:
// -----------------------------------------------------v
func NewHostUpTimeReporter(updateIntervalInSeconds int) *HostUptimeReporter {
instance := &HostUptimeReporter{updateInterval: updateIntervalInSeconds, shutdownSignal: make(chan bool), uptime:59}
// ---------^
...
- 1 回答
- 0 关注
- 73 浏览
添加回答
举报
0/150
提交
取消