在 Golang 中返回一个带有接收者的函数

Question

我是高朗的新手。我正在尝试使用一个装饰器，它返回一个带有接收器的函数。我怎样才能做到这一点？type myStruct struct {    s string}func myFunc(s string) {    fmt.Println(s)}// Here I want to return a function with a receiverfunc (*myStruct) myDecorator(fn func(string)) (*myStruct)func(string){    return (ms *myStruct)func(s string) {        fn(ms+s)    }}func main() {    ms := myStruct{"Hello"}    // Some func is function with receiver as myStruct pointer    someFunc := myDecorator(myFunc)    // This is expected to print "Hello world"    ms.someFunc(" world")}