我如何检查我的聊天机器人中的 2 个句子是否相似

Question

我使最简单的聊天机器人成为可能。它会根据您之前希望它回答同一问题的内容来回答您的问题。代码有点像这样：question = []answer = []qcount = 0stop = 0b = 0while stop == 0:    b = 0    q = input("Ask me anything: ")    if q == "stop":        exit()    for i in range(qcount):        if q == question[i]:            b = 1            print(answer[i])    if b == 0:        question.append(q)        qcount = qcount + 1        a = input("How should i answer that? ")        answer.append(a)有没有办法转if q == question[i]到if q is similar to question[i]?

Answer 1

我有类似的答案给你。你也可以试试这个。您不需要计数器和退出语句。您可以将 while 语句本身定义为看门人。

我做了一些更多的改进。虽然这不会给你一个完美的聊天机器人，但它更接近了。

question = []

answer = []

q = input("Ask me anything: ")

while q.lower() != 'stop':

    i = -1

    z = q.lower().split()

    z.sort()

    for x in question:

        y = x.split()

        y.sort()

        if all(elem in y for elem in z):

            i = question.index(x)

    if i >= 0:

        print(answer[i])

    else:

        question.append(q.lower())

        a = input("How should i answer that? ")

        answer.append(a)

    q = input("Ask me anything: ")

输出：

Ask me anything: What is your Name

How should i answer that? Joe

Ask me anything: What your name

Joe

Ask me anything: name

Joe

Ask me anything: your name

Joe

Ask me anything: what name

Joe

Ask me anything: what is name

Joe

如您所见，当您询问“姓名是什么”时，它仍然假定您是在询问您的姓名。您需要使用它来获得更复杂的机器人。希望这可以帮助您朝着正确的方向前进。

我之前的回答也贴在这里。由于我们将字符串与列表进行比较，因此它必须完全匹配。检查有问题的 q 并不能真正给你带来优势。您将需要拆分单词并进行比较。这就是我在新回复中所做的（见上文）

question = []

answer = []

q = input("Ask me anything: ")

while q.lower() != 'stop':

    if q.lower() in question:

        i = question.index(q.lower())

        print (answer[i])

    else:

        question.append(q.lower())

        a = input("How should i answer that? ")

        answer.append(a)

    q = input("Ask me anything: ")

Answer 2

使模糊查找器通过替换为此if q == question[i]不if q in question[i]查找特定单词但查找关键字来执行此操作

question = []

answer = []

qcount = 0

stop = 0

b = 0

while stop == 0:

    b = 0

    q = input("Ask me anything: ")

    if q == "stop":

        exit()

    for i in range(qcount):

         if q in question[i]:  # HERE IS THE ANSWER

            b = 1

            print(answer[i])

    if b == 0:

        question.append(q)

        qcount = qcount + 1

        a = input("How should i answer that? ")

        answer.append(a)