如何在包含占位符的字典中加载 yaml 文件内容？

Question

输入yaml文件kind: Testingmetadata:   name: test-file   annotations:      purpose: To test the deployed codespec:   containers:     - name: client       image: {{.registry}}/xyz:{{.client}}       env:         {{ if ne .proxy ""  }}         - name: http_proxy         value: "{{.proxy}}"         {{ end -}}我想加载字典中除占位符内容之外的所有 yaml 内容。我怎样才能实现它？我可以使用任何正则表达式来过滤占位符吗？我尝试使用以下代码，它适用于没有占位符值但在上述 yaml 中给出解析错误的 yaml。def __load_yaml(filename):  with open(filename, 'r') as stream:    try:        return yaml.load(stream, Loader=yaml.FullLoader)    except yaml.YAMLError as exception:        raise exception  def main():   data = {}   data.update(__load_yaml(file))   print(data) if __name__ == '__main__':   main()我也试过这个，它正在将 yaml 加载到字典中，但也给出了 FileNotFoundError。有没有办法将列表读取为流？或任何建议我怎样才能实现它？：def __load_yaml(filename):with open(filename, 'r') as stream:    try:        data = []        for text in stream:            match = re.search(r'\{\{.*?\}\}', text)            if not match and text != None:                data.append(text)        with open(str(data), 'r') as stream:            return yaml.load(stream, Loader=yaml.FullLoader)    except yaml.YAMLError as exception:        raise exception

Answer 1

def __load_yaml(filename):

  with open(filename, "r") as stream:

    string = stream.read()

    # Find placeholders

    reg_one = re.findall(r':\{\{.*?\}\}', string)

    reg_two = re.findall(r'\{\{.*?\}\}', string)

    placeholders = reg_one + reg_two

    # Replace placeholders

    for placeholder in placeholders:

        string = string.replace(placeholder, "")

    try:

        return yaml.load(string, Loader=yaml.FullLoader)

    except yaml.YAMLError as exception:

        raise exception