我有一个dll文件叫GetNum.dll，里面有个命令GetNum，怎样输出这个命令的结果？

Question

#include <WINDOWS.H>  #include <WINBASE.H>typedef void (*MYPROC)(char*); void main(){HINSTANCE LibHandle;MYPROC ProcAdd; char sysbuf[] = "GetNum"; /*过程名*/LibHandle = LoadLibrary("GetNum.dll"); /*载入dll*/ ProcAdd = (MYPROC)GetProcAddress(  LibHandle, sysbuf); /*获取函数sysbuf的地址*/}

Answer 1

GetNum.dll只是一个链接库，，你只能调用接口函数。看来你还不懂怎么调用动态链接库

Answer 2

根据我的猜测,有两种情况1.如果 void GetNum(char* s);是把输入的字符储存在 *s中的话:#include <WINDOWS.H>    #include <WINBASE.H>#include <stdio.h>    typedef void (*MYPROC)(char*); /* 这里要与GetNum的返回值和参数 对应 */void main(){   HINSTANCE LibHandle;   MYPROC ProcAdd;    char ch;       char sysbuf[] = "GetNum";   /*过程名*/   LibHandle = LoadLibrary("GetNum.dll"); /*载入dll*/        ProcAdd = (MYPROC)GetProcAddress(      LibHandle, sysbuf);   /*获取函数sysbuf的地址*/   ProcAdd(&ch);       printf("%c\n",ch);}

2.如果你的GetNum是int GetNum(char* s){    int i=0,ans=0;    while(s[i]>='0'&&s[i]<='9')    {        ans=s[i]-'0'+ans*10;    }    return ans;} #include <WINDOWS.H>    #include <WINBASE.H>#include <stdio.h>    typedef int  (*MYPROC)(char*);           /*   改 */void main(){   HINSTANCE LibHandle;   MYPROC ProcAdd;    char s[100];                        /*   改 */   char sysbuf[] = "GetNum";   /*过程名*/   LibHandle = LoadLibrary("GetNum.dll"); /*载入dll*/        ProcAdd = (MYPROC)GetProcAddress(      LibHandle, sysbuf);   /*获取函数sysbuf的地址*/   scanf("%s",s);                    /*   改 */   printf("%d\n", ProcAdd(&s) );        /* 这里调用 并输出结果 */}