如何循环遍历一个对象形成形成条件

Question

我有一个对象，如下所示：{    Condition0: "5"    Condition1: "6"    LogicalOperator0: "&&"    Operator0: "<"    Operator1: "!="    Question0: "How do you rate our services?"    Question1: "How likely are you to recommend our services to others?"}我想安排它形成一个条件Question0 Operator0 Condition0 LogicalOperator0 Question1 Operator1 Condition1 因此结果形成如下所示的比较运算符：How do you rate our services? < 5 && How likely are you to recommend our services to others? != 6任何人都请协助在 JS 中实现这一目标。

Answer 1

您可以为属性和数字部分采用嵌套循环，并将所有部分收集在一个数组中。

let data = { Condition0: "5", Condition1: "6", LogicalOperator0: "&&", Operator0: "<", Operator1: "!=", Question0: "How do you rate our services?", Question1: "How likely are you to recommend our services to others?" },

    keys = ['Question', 'Operator', 'Condition', 'LogicalOperator'],

    result = [],

    i = 0;

outer: while (true) {

    for (const part of keys) {

        const key = `${part}${i}`;

        if (!(key in data)) break outer;

        result.push(data[key]);

    }

    i++;

}

console.log(result.join(' '));

Answer 2

将对象分配给变量并从那里访问它：

var someName = {

    Condition0: "5"

    Condition1: "6"

    LogicalOperator0: "&&"

    Operator0: "<"

    Operator1: "!="

    Question0: "How do you rate our services?"

    Question1: "How likely are you to recommend our services to others?"

}

//Accessing the values would look like:

//someName.question0 + somename.operator0 + somename.condition0...

如果您遍历该对象，则只能按照创建它的顺序访问它。您似乎需要以不同的顺序访问它。

Answer 3

您可以将显示属性的顺序存储到一个数组中并操作该数组

const obj = {

  Condition0: '5',

  Condition1: '6',

  LogicalOperator0: '&&',

  Operator0: '<',

  Operator1: '!=',

  Question0: 'How do you rate our services?',

  Question1: 'How likely are you to recommend our services to others?'

}

const order = [

  'Question0',

  'Operator0',

  'Condition0',

  'LogicalOperator0',

  'Question1',

  'Operator1',

  'Condition1'

]

const res = order.map(prop => obj[prop]).join(' ')

console.log(res)