我有一组 3d 点S。我需要找到S中所有点集的集合X，这些点在曼哈顿距离d之内。即对于X中的每个集合Y，在 3d 空间中至少存在一个点在Y中所有点的距离d内集合S的长度永远不会 >20，但我将不得不对以每秒约 10 个新集合的速度生成的集合流运行此分析，因此无论我使用什么解决方案，都必须相当有效。一个帮助可视化问题的示例，给出以下内容：输出将是 ((A,B), (B,C,E), (B,D,E))我们只关心最大可能的集合，因此集合 (B,C)、(B,D)、(B,E)、(C,E) 和 (D,E) 在给定参数内不在给定它们是X中其他集合的子集的输出这也是我在 java 中做的，但是任何关于算法或伪代码的指针都将不胜感激，在此先感谢。
2 回答
Helenr
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伪代码的解决方案是：
calculate_intersections(areas):
intersections = calculate every two intersecting areas
combinations = combine_intersections(intersections)
reduced = remove all sets in combinations that are included in bigger sets
combine_intersections(intersections):
do:
combinations = new HashSet
for s1 in intersections:
for s2 in intersections:
diff_1_2 = s1 \ s2
diff_2_1 = s2 \ s1
if diff_1_2.len == 1 && diff_2_1.len == 1:
union = diff_1_2 + diff_2_1
if union in intersections:
union2 = s1 + s2
if !union2 in intersections:
combinations.add(union)
while (combinations not empty)
Java 中的实现可能如下所示：
import java.util.Arrays;
import java.util.HashSet;
import java.util.Iterator;
import java.util.Set;
import org.apache.commons.collections4.SetUtils;
public class IntersectionSetCalculation {
private static class ManhattanDistanceArea {
private String id;
private Vector3D center;
private double distance;
public ManhattanDistanceArea(Vector3D center, double distance, String id) {
this.center = center;
this.distance = distance;
this.id = id;
}
@Override
public String toString() {
return id;
}
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + ((center == null) ? 0 : center.hashCode());
long temp;
temp = Double.doubleToLongBits(distance);
result = prime * result + (int) (temp ^ (temp >>> 32));
result = prime * result + ((id == null) ? 0 : id.hashCode());
return result;
}
@Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
ManhattanDistanceArea other = (ManhattanDistanceArea) obj;
if (center == null) {
if (other.center != null)
return false;
}
else if (!center.equals(other.center))
return false;
if (Double.doubleToLongBits(distance) != Double.doubleToLongBits(other.distance))
return false;
if (id == null) {
if (other.id != null)
return false;
}
else if (!id.equals(other.id))
return false;
return true;
}
public boolean intersects(ManhattanDistanceArea other) {
double maxDist = distance + other.distance;
return center.distance(other.center, 1) < maxDist;
}
}
/**
* Calculate the intersection of all areas (maximum of 2 areas in an intersection)
*/
public static Set<Set<ManhattanDistanceArea>> getIntersectingAreas(Set<ManhattanDistanceArea> areas) {
Set<Set<ManhattanDistanceArea>> intersections = new HashSet<Set<ManhattanDistanceArea>>();
for (ManhattanDistanceArea area : areas) {
for (ManhattanDistanceArea area2 : areas) {
if (!area.equals(area2) && area.intersects(area2)) {
HashSet<ManhattanDistanceArea> intersection = new HashSet<ManhattanDistanceArea>();
intersection.add(area);
intersection.add(area2);
intersections.add(intersection);
}
}
}
Set<Set<ManhattanDistanceArea>> combined = combineIntersections(intersections);
Set<Set<ManhattanDistanceArea>> reduced = reduceIntersections(combined);
return reduced;
}
/**
* Combine the small intersections (with a maximum of 2 areas in an intersection) to bigger intersections
*/
public static Set<Set<ManhattanDistanceArea>> combineIntersections(Set<Set<ManhattanDistanceArea>> inters) {
Set<Set<ManhattanDistanceArea>> intersections = new HashSet<Set<ManhattanDistanceArea>>(inters);
Set<Set<ManhattanDistanceArea>> combinations;
do {
combinations = new HashSet<Set<ManhattanDistanceArea>>();
for (Set<ManhattanDistanceArea> intersecting1 : intersections) {
for (Set<ManhattanDistanceArea> intersecting2 : intersections) {
Set<ManhattanDistanceArea> diff_1_2 = SetUtils.difference(intersecting1, intersecting2);
Set<ManhattanDistanceArea> diff_2_1 = SetUtils.difference(intersecting2, intersecting1);
if (diff_1_2.size() == 1 && diff_2_1.size() == 1) {
Set<ManhattanDistanceArea> union_1_2 = SetUtils.union(diff_1_2, diff_2_1);
if (intersections.contains(union_1_2)) {
Set<ManhattanDistanceArea> union = SetUtils.union(intersecting1, intersecting2);
if (!intersections.contains(union)) {
combinations.add(union);
}
}
}
}
}
intersections.addAll(combinations);
} while (!combinations.isEmpty());
return intersections;
}
/**
* Remove the small intersections that are completely covered by bigger intersections
*/
public static Set<Set<ManhattanDistanceArea>> reduceIntersections(Set<Set<ManhattanDistanceArea>> inters) {
Set<Set<ManhattanDistanceArea>> intersections = new HashSet<Set<ManhattanDistanceArea>>(inters);
Iterator<Set<ManhattanDistanceArea>> iter = intersections.iterator();
while (iter.hasNext()) {
Set<ManhattanDistanceArea> intersection = iter.next();
for (Set<ManhattanDistanceArea> intersection2 : inters) {
if (intersection2.size() > intersection.size() && intersection2.containsAll(intersection)) {
iter.remove();
break;
}
}
}
return intersections;
}
public static void main(String[] args) {
final double dist = 2d;//the manhattan distance d
ManhattanDistanceArea A = new ManhattanDistanceArea(new Vector3D(0, -3, 0), dist, "A");
ManhattanDistanceArea B = new ManhattanDistanceArea(new Vector3D(0, 0, 0), dist, "B");
ManhattanDistanceArea C = new ManhattanDistanceArea(new Vector3D(3.5, 0, 0), dist, "C");
ManhattanDistanceArea D = new ManhattanDistanceArea(new Vector3D(0, 3.5, 0), dist, "D");
ManhattanDistanceArea E = new ManhattanDistanceArea(new Vector3D(1, 1, 0), dist, "E");
ManhattanDistanceArea F = new ManhattanDistanceArea(new Vector3D(-1, 1, 0), dist, "F");
//test the example you provided
Set<ManhattanDistanceArea> abcde = new HashSet<ManhattanDistanceArea>();
abcde.addAll(Arrays.asList(new ManhattanDistanceArea[] {A, B, C, D, E}));
//test another example
Set<ManhattanDistanceArea> abcdef = new HashSet<ManhattanDistanceArea>();
abcdef.addAll(abcde);
abcdef.add(F);
Set<Set<ManhattanDistanceArea>> intersectionsABCDE = getIntersectingAreas(abcde);
Set<Set<ManhattanDistanceArea>> intersectionsABCDEF = getIntersectingAreas(abcdef);
System.out.println(intersectionsABCDE);
System.out.println(intersectionsABCDEF);
//test the runntime for 1000 calculation
double startTime = System.currentTimeMillis();
final int calculations = 1000;
for (int i = 0; i < calculations; i++) {
Set<ManhattanDistanceArea> areas = new HashSet<ManhattanDistanceArea>();
for (int j = 0; j < 20; j++) {
areas.add(new ManhattanDistanceArea(new Vector3D(Math.random() * 10 - 5, Math.random() * 10 - 5, Math.random() * 10 - 5), dist,
"A" + j));
}
getIntersectingAreas(areas);
}
System.out.println("\nTime used for " + calculations + " intersection calculations (with sets of size 20): "
+ (System.currentTimeMillis() - startTime) + "ms");
}
}
对于我使用此类 Vector3D 的实现：
public class Vector3D {
public double x;
public double y;
public double z;
public static final Vector3D NAN_VEC = new Vector3D(Double.NaN, Double.NaN, Double.NaN);
public static final Vector3D NULL_VEC = new Vector3D(0, 0, 0);
public enum Axis {
X, Y, Z;
}
public Vector3D() {
}
/**
* Crate a new Vector2D with x and y components.
*/
public Vector3D(double x, double y, double z) {
this.x = x;
this.y = y;
this.z = z;
}
public Vector3D(double... val) {
x = val[0];
y = val[1];
z = val[2];
}
/**
* Create a Vector3D by two angles (in degree).
*
* The first angle is in XY direction. The second angle is the Z direction.
*
* An angle (XY) of 0° results in (x, y) = (1, 0); 90° in (x, y) = (0, 1); ... An angle (Z) of 0° results in (x, y, z) = (x, y, 0); 90° in (x, y,
* z) = (x, y, 1); -90° in (x, y, z) = (x, y, -1)
*
* The resulting vector has a length of 1.
*
* @param angleXY
* The angle of the new vector (in degree) for the XY direction (from 0 to 360).
*
* @param angleZ
* The angle of the new vector (in degree) for the Z direction (from -90 to 90).
*/
public Vector3D(double angleXY, double angleZ) {
x = Math.cos(angleXY * Math.PI / 180) * Math.cos(angleZ * Math.PI / 180);
y = Math.sin(angleXY * Math.PI / 180) * Math.cos(angleZ * Math.PI / 180);
z = Math.sin(angleZ * Math.PI / 180);
double len = length();
x /= len;
y /= len;
z /= len;
}
private Vector3D(Vector3D clone) {
this.x = clone.x;
this.y = clone.y;
}
@Override
public Vector3D clone() {
return new Vector3D(this);
}
@Override
public String toString() {
return "Vector3D[x: " + x + " y: " + y + " z:" + z + "]";
}
@Override
public boolean equals(Object obj) {
if (obj instanceof Vector3D) {
Vector3D v = (Vector3D) obj;
return Math.abs(x - v.x) < 1e-8 && Math.abs(y - v.y) < 1e-8 && Math.abs(z - v.z) < 1e-8;
}
return false;
}
/**
* Get this vector as 3D-Array.
*/
public double[] asArray() {
return new double[] {x, y, z};
}
/**
* The (euclidean) length of the Vector.
*/
public double length() {
return Math.sqrt(Math.pow(x, 2) + Math.pow(y, 2) + Math.pow(z, 2));
}
/**
* The length of this vector in a given norm.
*
* @param norm
* The norm of the vector length.
*
* @return The length of this vector in the given norm.
*/
public double length(int norm) {
if (norm == Integer.MAX_VALUE) {
return Math.max(Math.max(x, y), z);
}
return Math.pow(Math.pow(x, norm) + Math.pow(y, norm) + Math.pow(z, norm), 1.0 / norm);
}
/**
* Rotate this vector an angle (in degrees) around an axis resulting in a new Vector that is returned.
*
* @param degrees
* The angle to return the vector.
*
* @param axis
* The axis around which the vector is rotated.
*
* @return The new created vector.
*/
public Vector3D rotate(double degrees, Axis axis) {
double cos = Math.cos(degrees * Math.PI / 180);
double sin = Math.sin(degrees * Math.PI / 180);
switch (axis) {
case X:
return new Vector3D(x, cos * y - sin * z, sin * y + cos * z);
case Y:
return new Vector3D(cos * x + sin * z, y, -sin * x + cos * z);
case Z:
return new Vector3D(cos * x - sin * y, sin * x + cos * y, z);
default:
return null;
}
}
/**
* Project the vector given as parameter on this vector.
*
* @param vec
* The vector that is to be projected on this vector.
*
* @return The projected vector.
*/
public Vector3D project(Vector3D vec) {
return mult(scalar(vec) / Math.pow(length(), 2));
}
/**
* Add another Vector3D to this vector resulting in a new Vector that is returned.
*
* @param vec
* The vector added to this vector.
*
* @return The new created vector.
*/
public Vector3D add(Vector3D vec) {
return new Vector3D(x + vec.x, y + vec.y, z + vec.z);
}
/**
* Subtract another Vector3D from this vector resulting in a new Vector that is returned.
*
* @param vec
* The vector subtracted from this vector.
*
* @return The new created vector.
*/
public Vector3D sub(Vector3D vec) {
return new Vector3D(x - vec.x, y - vec.y, z - vec.z);
}
/**
* Multiply this vector with a scalar resulting in a new Vector that is returned.
*
* @param scalar
* The scalar to multiply this vector with.
*
* @return The new created vector.
*/
public Vector3D mult(double scalar) {
return new Vector3D(x * scalar, y * scalar, z * scalar);
}
/**
* Check whether this vector is linearly dependent to the parameter vector.
*
* @param vec
* The checked vector.
*
* @return True if the vectors are linearly dependent. False otherwise.
*/
public boolean isLinearlyDependent(Vector3D vec) {
double t1 = (x == 0 ? 0 : vec.x / x);
double t2 = (y == 0 ? 0 : vec.y / y);
double t3 = (z == 0 ? 0 : vec.z / z);
return Math.abs(t1 - t2) < 1e-5 && Math.abs(t1 - t3) < 1e-5 && t1 != 0;//all parameters t are equal and != 0
}
/**
* Calculate the scalar product of this vector and the parameter vector.
*
* @param vec
* The vector to calculate the scalar with this vector.
*
* @return The scalar of the vectors.
*/
public double scalar(Vector3D vec) {
return this.x * vec.x + this.y * vec.y + this.z * vec.z;
}
/**
* Calculate the cross product of this vector with another vector (resulting vector = this X parameter vector)
*
* @param vec
* The second vector for the cross product calculation.
*
* @return The cross product vector of the two vectors.
*/
public Vector3D cross(Vector3D vec) {
return new Vector3D(y * vec.z - z * vec.y, z * vec.x - x * vec.z, x * vec.y - y * vec.x);
}
/**
* Create a new vector with the same direction but a different length as this vector.
*
* @param length
* The length of the new vector.
*
* @return The new vector with a new length.
*/
public Vector3D setLength(double length) {
double len = length();
return new Vector3D(x * length / len, y * length / len, z * length / len);
}
/**
* Get the distance of this point's position vector to another point's position vector.
*
* @param p
* The second point's position vector.
*
* @return The distance between the points.
*/
public double distance(Vector3D p) {
return Math.sqrt((this.x - p.x) * (this.x - p.x) + (this.y - p.y) * (this.y - p.y) + (this.z - p.z) * (this.z - p.z));
}
/**
* Get the distance of this point's position vector to another point's position vector in a given norm.
*
* @param p
* The second point's position vector.
*
* @param norm
* The norm in which the distance is calculated (1 -> manhattan, 2 -> euclide, ...)
*
* @return The distance between the points in the given norm.
*/
public double distance(Vector3D p, int norm) {
return Math.pow((Math.pow(Math.abs(this.x - p.x), norm) + Math.pow(Math.abs(this.y - p.y), norm) + Math.pow(Math.abs(this.z - p.z), norm)),
1d / norm);
}
/**
* Change this vector to the new coordinates.
*/
public void move(double x, double y, double z) {
this.x = x;
this.y = y;
this.z = z;
}
/**
* Move a point's position vector in a direction (by a vector) and a distance.
*
* @param p
* The direction vector.
*
* @param distance
* The distance to move the new vector
*
* @return The new created vector.
*/
public Vector3D moveTo(Vector3D p, double distance) {
double d = distance(p);
double dx = p.x - x;
double dy = p.y - y;
double dz = p.z - z;
double coef = distance / d;
return new Vector3D(x + dx * coef, y + dy * coef, z + dz * coef);
}
/**
* Get the angle difference of this vector to another vector.
*
* @param vec
* The other vector.
*
* @return The angle difference of the two vectors (from 0° to 180°).
*/
public double getAngleTo(Vector3D vec) {
double angle = Math.acos(scalar(vec) / (length() * vec.length())) * 180 / Math.PI;
if (angle > 180) {
angle = 360 - angle;
}
return angle;
}
/**
* Get the vector from this point to another.
*
* @param vec
* The point to which the vector is calculated.
*
* @return The vector from this points position vector to the other point.
*/
public Vector3D vectorTo(Vector3D vec) {
return new Vector3D(vec.x - x, vec.y - y, vec.z - z);
}
/**
* Checks whether a point (by its position vector) is in a given range of this point.
*
* @param p
* The point that is checked.
*
* @param range
* The range used for the check.
*
* @return True if the point is in the range of this point (distance <= range).
*/
public boolean isInRange(Vector3D p, double range) {
return p != this && distance(p) <= range;
}
}
和apache 公共库中的SetUtils类。
我还添加了一些测试：
你的问题的测试
另一个具有更大交叉集的测试
运行时测试
结果是：
[[A, B], [B, E, C], [B, E, D]]
[[A, B], [B, E, C], [D, E, F, B]]
用于 1000 个交点计算的时间（大小为 20 的集合）：791.0ms
所以结果似乎是正确的，你可以在一秒钟内计算出 1000 多个交叉点。
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