如何让第二辆车说第二名？

Question

我想做的是所以我基本上想做的是每次一辆车越过终点 它说哪辆车有一个但我想做的是每次第一辆车获胜并且第二辆车越过终点线我想要它说哪辆车排在第二位和第三位等等import pygame, randompygame.init()# musicmusic = pygame.mixer.music.load(“image/Led Zeppelin - Rock And Roll (Alternate Mix) (Official Music Video).mp3”)pygame.mixer.music.play(-1)#Setting up our colors that we are going to useGREEN = (20, 255, 140)GREY = (210, 210, 210)WHITE = (255, 255, 255)RED = (255, 0, 0)PURPLE = (255, 0, 255)BLACKWHITE =(96, 96, 96)SCREENWIDTH = 400SCREENHEIGHT = 500size = (SCREENWIDTH, SCREENHEIGHT)screen = pygame.display.set_mode(size)pygame.display.set_caption("Car Racing")Icon = pygame.image.load("image/redca_iconr.png")pygame.display.set_icon((Icon))# This will be a list that will contain all the sprites we intend to use in our game.#all_sprites_list = pygame.sprite.Group()#playerplayerIMG = pygame.image.load("image/red_racecar.png")playerX = 250playerY = 450playerCar_position = 0#player2playerIMG_two = pygame.image.load("image/greencar.png")playerX_two = 150playerY_two = 450playerCar_position_two = 0#player3playerIMG_three = pygame.image.load("image/Orangecar.png")playerX_three = 50playerY_three = 450playerCar_position_three = 0#player4playerIMG_four = pygame.image.load("image/yellow_car.png")playerX_four = 200playerY_four = 450playerCar_position_four = 0#Putting cars to the screendef player(x, y):    screen.blit(playerIMG, (x, y))def player_two(x, y):    screen.blit(playerIMG_two, (x, y))def player_three(x, y):    screen.blit(playerIMG_three, (x, y))def player_four(x, y):    screen.blit(playerIMG_four, (x, y))

Answer 1

所以，你得到的代码有效，唯一的问题是当汽车与终点线相交时，你只在屏幕上显示文本

因此，每帧都有一个字符串放在屏幕上，当汽车越过这条线时，将字符串更改为那辆车

#put these outside the game loop

finish_text = ""

font2 = pygame.font.SysFont("Papyrus", 45)

players_finished = 0

placings = ["1st", "2nd", "3rd", "4th"]

while running: #game loop

...

     # Did anyone cross the line?

    if (finish_line_rect.collidepoint(playerX, playerY)):

        if finish_text[:9] != "Player 1": #so it doesnt do this every frame the car is intersecting

            finish_text = "Player 1 is " + placings[players_finished]

            players_finished += 1

            print("Player (one) has crossed into finish line!")

    elif (finish_line_rect.collidepoint(playerX_two , playerY_two)):

        if finish_text[:9] != "Player 2":

            print("Player one has crossed into finish line first other car lost!")

            finish_text = "Player 2 is " + placings[players_finished]

            players_finished += 1

    elif (finish_line_rect.collidepoint(playerX , playerY)):

        if finish_text[:9] != "Player 3":

            print("Player two has crossed into finish line first other car lost!")

            finish_text = "Player 3 is " + placings[players_finished]

            players_finished += 1

    elif (finish_line_rect.collidepoint(playerX_two, playerY_two)):

        if finish_text[:9] != "Player 4":

            print("Player two has crossed into finish line first other car lost!")

            finish_text = "Player 4 is " + placings[players_finished]

            players_finished += 1

    

    if finish_text != "": #test to see if there is anything to put on screen

        text2 = font2.render(finish_text, 5, (255, 99, 7))

        screen.blit(text2, (135 - (text2.get_width() / 5), 95))

    pygame.display.flip()

笔记。还没有测试过

Answer 2

我从未使用过 pygame，所以不知道是否有内置函数。但是，您可以轻松地制作一个计数器。

#this is all in your while loop

if playerY<50 or playerY_two<50 or playerY_three<50 or playerY_four<50:

        count+=1

        if count == 1:

            if playerY<50:

                print('playerY first place')

                playerY=10000

            if playerY_two<50:

                print('playerY_two first place')

                playerY_two=100000

            if playerY_three<50:

                print('playerY_three first place')

                playerY_three=100000

            if playerY_four<50:

                print('playerY_four first place')

                playerY_four=1000000

        if count == 2:

            if playerY<50:

                print('playerY second place')

                playerY=10000

            if playerY_two<50:

                print('playerY_two seoncd place')

                playerY_two=100000

            if playerY_three<50:

                print('playerY_three second place')

                playerY_three=100000

            if playerY_four<50:

                print('playerY_four second place')

                playerY_four=1000000

        if count == 3:

            if playerY<50:

                print('playerY third place')

                playerY=10000

            if playerY_two<50:

                print('playerY_two third place')

                playerY_two=100000

            if playerY_three<50:

                print('playerY_three third place')

                playerY_three=100000

            if playerY_four<50:

                print('playerY_four third place')

                playerY_four=1000000

        if count == 4:

            if playerY<50:

                print('playerY 4th place')

                playerY=10000

            if playerY_two<50:

                print('playerY_two 4th place')

                playerY_two=100000

            if playerY_three<50:

                print('playerY_three 4th place')

                playerY_three=100000

            if playerY_four<50:

                print('playerY_four 4th place')

                playerY_four=1000000

            break   

你可以创建一个类/函数来将上面的全部内容写成 4 行到 5 行，但一般的想法是你想打印出谁越过终点线，但你只希望打印一次。