从文件中读取字典后打印多个值

Question

我无法为我正在编写的程序提出解决方案。我正在阅读 pom 文件中的礼仪，我将它们保存到字典中。将它们保存到字典后，我想以特定方式输出。如下：我如何解析 pom 文件的代码：for dep in depend:    infoList = []    counter += 1    for child in dep.getchildren():        infoList.append(child.tag.split('}')[1])        infoList.append(child.text)    #list where data is being stored    dependencyInfo[infoList[1]].update({infoList[2] : infoList[3],infoList[4] : infoList[5]})                   #print statement of all the dataprint("""%i Dependency where found in %s's pom file.""" % (counter,projectName))print(dependencyInfo)输出是11 Dependency where found in my-application1's pom file.defaultdict(<class 'dict'>, {'junit': {'artifactId': 'junit', 'version': '3.8.1'}, 'org.hibernate': {'artifactId': 'ejb3-persistence', 'version': '1.0.1.GA'}, 'javax.sql': {'artifactId': 'jdbc-stdext', 'version': '2.0'}, 'javax.transaction': {'artifactId': 'jta', 'version': '1.0.1B'}, 'mysql': {'artifactId': 'mysql-connector-java', 'version': '5.1.14'}, 'slf4j-api': {'groupId': 'org.slf4j', 'type': 'jar'}, 'org.slf4j': {'artifactId': 'slf4j-simple', 'version': '1.6.1'}})现在我想按如下方式重新排列数据groupId = junitartifactId = junitversion = 3.8.1..groupId = javax.transaction artifactId = jtaversion = 1.0.1B

Answer 1

您可以使用f-strings执行此操作：

for groupId, artifact in dependencyInfo.items():

    artifactId = artifact["artifactId"]

    version = artifact["version"]

    print(f"groupId = {groupId}")

    print(f"artifactId = {artifactId}")

    print(f"version = {version}")

    print()

请注意，您dependencyInfo有一个小错误，此条目：'slf4j-api': {'groupId': 'org.slf4j', 'type': 'jar'}需要artifactId在正文中代替并groupId作为键。

为了适应 wheregroupId和artifactId可以切换，除了 等其他字段type，您可以使用这个：

for dependencyId, info in dependencyInfo.items():

    additionalInfo = {}

    groupId = None

    artifactId = None

    for infoName, infoValue in info.items():

        if infoName == "artifactId":

            artifactId = info["artifactId"]

            groupId = dependencyId

        elif infoName == "groupId":

            artifactId = dependencyId

            groupId = info["groupId"]

        else:

            additionalInfo[infoName] = infoValue

    if groupId:

        print(f"groupId = {groupId}")

    if artifactId:

        print(f"artifactId = {artifactId}")

    for infoName, infoValue in additionalInfo.items():

        print(f"{infoName} = {infoValue}")

    print()

您的结果输出dependencyInfo：

groupId = junit

artifactId = junit

version = 3.8.1

groupId = org.hibernate

artifactId = ejb3-persistence

version = 1.0.1.GA

groupId = javax.sql

artifactId = jdbc-stdext

version = 2.0

groupId = javax.transaction

artifactId = jta

version = 1.0.1B

groupId = mysql

artifactId = mysql-connector-java

version = 5.1.14

groupId = org.slf4j

artifactId = slf4j-api

type = jar

groupId = org.slf4j

artifactId = slf4j-simple

version = 1.6.1

如果两者都不存在，或者两者同时存在于体内，这将产生意想不到的groupId结果artifactId。