如果在 n 行之前找到其他字符串，则 php regex 查找字符串

Question

我正在尝试将 mkvinfo 输出中的每一种音频和字幕语言都放入数组中，我已经尝试了各种谷歌搜索和 RegExr 上的正则表达式组合，但没有成功。我的源字符串是| + Muxing application: libmkv 0.6.5| + Writing application: HandBrake rev5474| + Timecode scale: 1000000| + Duration: 6788.031s (01:53:08.031)|+ Segment tracks| + A track|  + Track number: 1 (track ID for mkvmerge & mkvextract: 0)|  + Track UID: 718870071|  + Track type: video|  + Lacing flag: 0|  + Codec ID: V_MPEG4/ISO/AVC|  + CodecPrivate, length 45 (h.264 profile: High @L3.1)|  + Default duration: 41.708ms (23.976 frames/fields per second for a video track)|  + Default flag: 1|  + MinCache: 1|  + Video track|   + Pixel width: 1280|   + Pixel height: 536|   + Display width: 1280|   + Display height: 536| + A track|  + Track number: 2 (track ID for mkvmerge & mkvextract: 1)|  + Track UID: 1000053498|  + Track type: audio|  + Lacing flag: 0|  + Codec ID: A_AAC|  + CodecPrivate, length 2|  + Language: fre|  + Default flag: 1|  + Audio track|   + Sampling frequency: 48000|   + Channels: 2| + A track|  + Track number: 3 (track ID for mkvmerge & mkvextract: 2)|  + Track UID: 1097600287|  + Track type: audio|  + Lacing flag: 0|  + Codec ID: A_AAC|  + CodecPrivate, length 2|  + Language: eng|  + Default flag: 0|  + Audio track|   + Sampling frequency: 48000|   + Channels: 2| + A track|  + Track number: 4 (track ID for mkvmerge & mkvextract: 3)|  + Track UID: 1976675274|  + Track type: subtitles|  + Lacing flag: 0|  + Codec ID: S_TEXT/UTF8|  + Language: fre|  + Default flag: 0| + A track|  + Track number: 5 (track ID for mkvmerge & mkvextract: 4)|  + Track UID: 1930079859|  + Track type: subtitles|  + Lacing flag: 0|  + Codec ID: S_TEXT/UTF8|  + Language: fre|  + Default flag: 0|+ Cluster使用正则表达式Language:\s([a-z]+)我可以获得所有音频和字幕Language: freLanguage: engLanguage: freLanguage: fre理想的输出是Array(    [audio] => Array        (            [0] => eng            [1] => fre        )    [subtitles] => Array        (            [0] => fre            [1] => fre        ))任何帮助将不胜感激，提前致谢，最好

Answer 1

您可以使用交替来匹配 2 个捕获组中的任一值，并使用点匹配换行符(?s)

然后，您可以使用组 1 作为键来组装结果数组，并将组 2 的值添加到组 1 键。

(?s)\+\h+Track type:\h+(audio|subtitles)\b.*?\+\h+Language:\h+([a-z]+)

例如

preg_match_all($re, $str, $matches, PREG_SET_ORDER, 0);

$result = [];

foreach ($matches as $match) {

    $result[$match[1]][] = $match[2];

}

print_r($result);

输出

Array

(

    [audio] => Array

        (

            [0] => fre

            [1] => eng

        )

    [subtitles] => Array

        (

            [0] => fre

            [1] => fre

        )

)

不需要的更精确的模式可以(?s)匹配Track type:和匹配所有不以 A track 或 Language 开头的行：

^\|\h+\+\h+Track type:\h+(audio|subtitles)(?:\R(?!\|\h+\+\h+(?:[A-Z] track$|Language:)).*)*\R\|\h+\+ Language:\h+([a-z]+)