Pynput 按键延迟和 Tkinter

Question

我只是想制作一个程序来执行一些键盘输入。我想在每次击键之间设置一个延迟，我计划在将来随机设置。但是，我不确定如何after()与 Tkinter 一起使用。没有 Tkinter，time.sleep工作正常 - 但有了它，GUI 崩溃了。任何帮助，将不胜感激。import timeimport tkinter as tkfrom pynput.keyboard import Key, Controller as KeyboardControllerfrom pynput.mouse import Button, Controller as MouseControllerkeyboard = KeyboardController()mouse = MouseController()def copy(a):    pause_input=17    pause_input2=2    pause_input3=0.5    x=1    while a >= x:        x = x+1        time.sleep(pause_input)        keyboard.press('t')        keyboard.release('t')        time.sleep(pause_input3)        keyboard.press('e')        keyboard.release('e')        time.sleep(pause_input3)        keyboard.press('s')        keyboard.release('s')        keyboard.press('t')        keyboard.release('t')        root = tk.Tk()root.title("GUI Button")btn1 = tk.Button(root, text="Button 1", command=lambda : copy(360))btn2 = tk.Button(root, text="Button 2")btn1.pack()btn2.pack()root.mainloop()

Answer 1

首先：gui 不会崩溃 - 它工作正常并且在主循环中它执行您正在编写的命令。它不会刷新，因为它打印输出而不是刷新 UI。首先请注意，在创建 UI 时需要记住的是，您应该省略主线程中不必要的工作。可能的解决方案：将工作移至单独的线程并在那里运行，例如：

import time

import tkinter as tk

from pynput.keyboard import Controller as KeyboardController

import threading

keyboard = KeyboardController()

def copy(a):

    def print_test(a):

        pause_input=2

        pause_input2=2

        pause_input3=0.5

        for _ in range(a):

            time.sleep(pause_input)

            keyboard.press('t')

            keyboard.release('t')

            time.sleep(pause_input3)

            keyboard.press('e')

            keyboard.release('e')

            time.sleep(pause_input3)

            keyboard.press('s')

            keyboard.release('s')

            keyboard.press('t')

            keyboard.release('t')

            print("Wrote test")

    t = threading.Thread(target=print_test, args=(a,))

    t.start()

        

root = tk.Tk()

root.title("GUI Button")

btn1 = tk.Button(root, text="Button 1", command=lambda : copy(360))

btn1.pack()

root.mainloop()