甚至在循环外运行的方法

Question

我有这个方法可以作为其他方法的菜单：public static void menu(){    boolean works = true;    System.out.println("\n1 - Register Car\t2 - Register Client\t3 - Rent car\n4 - Returning car\t5 - Show list\t6 - Exit\n");    System.out.print("Input: ");    int operacao = scan.nextInt();    do {        if (operacao == 1) {            cadVeiculo();        } else if (operacao == 2) {            cadCliente();        } else if (operacao == 3) {            locar();        } else if (operacao == 4) {            devolver();        } else if (operacao == 5) {            listar();        } else if (operacao == 6){            works= false;        }    } while (works);}我不明白的是，当我运行程序并按“6”时，程序停止了，好的。但是当我按“1”注册汽车然后按“6”退出程序时，程序一直要求我输入另一个输入。我所期望的是，当我运行该程序并按“6”退出时，它只会完全停止该程序。

Answer 1

在do-while循环中移动println和行：scanner.nextInt()

这是一个仅打印出方法名称的修改示例：

import java.util.Scanner;

class Main {

  public static void main(String[] args) {

    menu();

  }

  public static void menu() {

    Scanner scan = new Scanner(System.in);

    boolean works = true;

    do {

      System.out.println(

          "\n1 - Register Car\t2 - Register Client\t3 - Rent car\n4 - Returning car\t5 - Show list\t6 - Exit\n");

      System.out.print("Input: ");

      int operacao = scan.nextInt();

      if (operacao == 1) {

        System.out.println("cadVeiculo();");

      } else if (operacao == 2) {

        System.out.println("cadCliente();");

      } else if (operacao == 3) {

        System.out.println("locar();");

      } else if (operacao == 4) {

        System.out.println("devolver();");

      } else if (operacao == 5) {

        System.out.println("listar();");

      } else if (operacao == 6) {

        System.out.println("Goodbye!");

        works = false;

      }

    } while (works);

    scan.close();

  }

}

用法示例：

1 - Register Car    2 - Register Client 3 - Rent car

4 - Returning car   5 - Show list   6 - Exit

Input: 1

cadVeiculo();

1 - Register Car    2 - Register Client 3 - Rent car

4 - Returning car   5 - Show list   6 - Exit

Input: 3

locar();

1 - Register Car    2 - Register Client 3 - Rent car

4 - Returning car   5 - Show list   6 - Exit

Input: 4

devolver();

1 - Register Car    2 - Register Client 3 - Rent car

4 - Returning car   5 - Show list   6 - Exit

Input: 6

Goodbye!