如何迭代打印多个值的过程？

Question

在这段 golang 代码中，我要求一个人输入他的名字。输入名称后，数据将从values1变量中获取，结果，它们将像这样使用给定的键打印出来给定结果Enter your name: samenameHere is the name: samenameHere is the email address: email oneHere is the job role: job one我还想打印values2被注释的变量的数据。同样，如果我有值的数量，我是否必须一次又一次n地重复？for i := range values1要求的结果Enter your name: samenameHere is the name: samenameHere is the email address: email oneHere is the job role: job role oneHere is the name: samenameHere is the email address: email twoHere is the job role: job role two......代码package mainimport "fmt"func main() {    var name string    keys := [3]string{"name", "email address", "job role"}    values1 := [3]string{"samename", "email one", "job role one"}    // values2 := [3]string{"samename", "email two", "job role two"}    for {        fmt.Printf("Enter your name: ")        fmt.Scanln(&name)        fmt.Println()        if name == values1[0] {            for i := range values1 {                // j is index into keys                j := i % len(keys)                // Print blank line between groups.                if j == 0 && i > 0 {                    fmt.Println()                }                fmt.Printf("Here is the %s: %s\n", keys[j], values1[i])            }            break        } else {            fmt.Println("Name is not found. Try again!")        }    }}

Answer 1

如果您需要打印密钥，也许您可以使用map. 你可以打印键和map值。

package main

import "fmt"

func main() {

    var name string

    value1 := map[string]string{"name": "samename", "email": "email one", "role": "job role one"}

    value2 := map[string]string{"name": "samename", "email": "email two", "role": "job role two"}

    values := []map[string]string{value1, value2}

    var found bool

    for {

        fmt.Printf("Enter your name: ")

        fmt.Scanln(&name)

        fmt.Println()

        for _, value := range values {

            if value["name"] == name {

                found = true

                for k, v := range value {

                    fmt.Printf("Here is the %s: %s\n", k, v)

                }

                fmt.Println()

            }

        }

        if found {

            break

        } else {

            fmt.Println("Name is not found. Try again!")

        }

    }

}