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Golang多维切片成预期的输出字符串json

Golang多维切片成预期的输出字符串json

Go
Cats萌萌 2022-12-26 16:50:41
在我的 Go 代码中,我有字符串的多维切片input := [][]string{    {"foods", "food by cooking technique", "baked food"},    {"foods", "food by cooking technique", "baked beans"},    {"foods", "food by type", "dried food"},    {"drinks", "hot drinks", "tea"},    {"drinks", "hot drinks", "herbal tea"},    {"drinks", "cold drinks", "ice cream drinks"},}如何转换为 json 以便生成的打印输出符合预期。也许递归{    "data": [      {        "name": "foods",        "data": [          {            "name": "food by cooking technique",            "data": [              { "name": "baked food" },              { "name": "baked beans" }            ]          },          {            "name": "food by type",            "data": [              { "name": "dried food" }            ]          }        ]      },      {        "name": "drinks",        "data": [          {            "name": "hot drinks",            "data": [              { "name": "tea" },              { "name": "herbal tea" }            ]          },          {            "name": "cold drinks",            "data": [              { "name": "ice cream drinks" }            ]          }        ]      }    ]}还没有想出这方面的想法,感谢您的帮助
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芜湖不芜

TA贡献1796条经验 获得超7个赞

速度不快,但可以理解的方法:


package main


import (

    "encoding/json"

    "log"

)


type mapStruct struct {

    Data map[string]*mapStruct

}


type dataStruct struct {

    Name string        `json:"name,omitempty"`

    Data []*dataStruct `json:"data,omitempty"`

}


func main() {


    input := [][]string{

        {"foods", "food by cooking technique", "baked food"},

        {"foods", "food by cooking technique", "baked beans"},

        {"foods", "food by type", "dried food"},

        {"drinks", "hot drinks", "tea"},

        {"drinks", "hot drinks", "herbal tea"},

        {"drinks", "cold drinks", "ice cream drinks"},

    }


    data := &mapStruct{}


    for _, v := range input {

        temp := data

        for _, vv := range v {

            if temp.Data == nil {

                temp.Data = map[string]*mapStruct{}

            }

            if _, ok := temp.Data[vv]; !ok {

                temp.Data[vv] = &mapStruct{}

            }

            temp = temp.Data[vv]

        }

    }


    output := &dataStruct{}


    fun(output, data)


    bts, err := json.MarshalIndent(output, "", "\t")

    if err != nil {

        log.Println(err)

        return

    }

    log.Println(string(bts))


}


func fun(d *dataStruct, m *mapStruct) {

    for k, v := range m.Data {

        d.Data = append(d.Data, &dataStruct{})

        d.Data[len(d.Data)-1].Name = k

        fun(d.Data[len(d.Data)-1], v)

    }

}


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反对 回复 2022-12-26
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