PHP encodeURIComponent 重置

Question

<a href="{{ payment.approve}}" class="pointer"><i class="fa fa-ban color-red"></i> Approve Payment</a><a href="{{ payment.reject}}" class="pointer"><i class="fa fa-ban color-red"></i> Reject Payment</a><script>    if (filterpayment) {        url += '&filterpayment=' + encodeURIComponent(filterpayment);    }</script>使用过滤器后”我的网址将是这样的http://localhost/index.php?route=sales/filterpayment&user_token=XXXXXX&filterpayment=2&page=2对于第 2 页是“分页”我想要的是，在执行操作（例如单击批准）后，如何在不删除“page2”的情况下重置它单击后我想要的是：批准http://localhost/index.php?route=sales/filterpayment&user_token=XXXXXX&page=2我试过的：url = 'index.php?route=sales/filterpayment&user_token={{ user_token }}';location = url;但它会直接重置 URL 中的“page2”并变成这个http://localhost/index.php?route=sales/filterpayment&user_token=XXXXXX

Answer 1

使用搜索参数

let url = new URL("http://localhost/index.php?route=sales/filterpayment&user_token=XXXXXX&page=2")

let filterpayment = 2;

if (filterpayment) {

  url.searchParams.set("filterpayment",encodeURIComponent(filterpayment));

}

console.log(url)

filterpayment = 0;

if (filterpayment) {

  url.searchParams.set("filterpayment",encodeURIComponent(filterpayment));

}

else {

  url.searchParams.delete("filterpayment");

}

console.log(url)